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Java replace string string by other string


Java replace string string by other string

By : harta bet
Date : November 21 2020, 09:01 AM
will be helpful for those in need I want to replace 1 by 1Min, 5 by 5Min, 10 by 10Min, 15 by 15Min,60 by 1Hour, 360 by 6Hours etc. , You could try something like this:
code :
String str = "15";
int minutes = Integer.parseInt(str);
if (minutes < 60)
    str += "Mins";
else
    str = (minutes/60) + "Hrs";
str = Integer.parseInt(str) < 60 ? str+"Mins" : (Integer.parseInt(str)/60) + (Integer.parseInt(str)/60 == 1 ? "Hr" : "Hrs");
int minutes = Integer.parseInt(str);
str = minutes < 60 ? str+"Mins" : (minutes/60) + (minutes/60 == 1 ? "Hr" : "Hrs");


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string& and char* version of string::append(), string::replace() and string::compare()

string& and char* version of string::append(), string::replace() and string::compare()


By : Bob Martin
Date : March 29 2020, 07:55 AM
should help you out The two overloaded function in std::string got my attention: , Because you can just add pos to s:
code :
str.append(ptr + pos, len);
java. is there any google's guava interface to replace Map<String, Map<String, String>>?

java. is there any google's guava interface to replace Map<String, Map<String, String>>?


By : Nisala weerasekara
Date : March 29 2020, 07:55 AM
wish helps you Yes, it's called Table:
code :
Table<Vertex, Vertex, Double> weightedGraph = HashBasedTable.create();
weightedGraph.put(v1, v2, 4);
weightedGraph.put(v1, v3, 20);
weightedGraph.put(v2, v3, 5);

weightedGraph.row(v1); // returns a Map mapping v2 to 4, v3 to 20
weightedGraph.column(v3); // returns a Map mapping v1 to 20, v2 to 5
How to replace a specific occurrence of a sub-string in a string and ignoring incomplete matches in java?

How to replace a specific occurrence of a sub-string in a string and ignoring incomplete matches in java?


By : ArtDude
Date : March 29 2020, 07:55 AM
I hope this helps . Use regex. For you example "\bod\b" will just match od as a whole word. \b is a word boundary, meaning either the start or the end of a word (whether it ends with a dot or a whitespace or anything else).
The replaceAll method can already take in a regex, but if you need more power you can look at the Matcher class.
code :
String REPLACE_WORD = "od"
sentence.replaceAll("\\b" + REPLACE_WORD + "\\b", "odd");
String Formatting in java to replace the array index with the pointed string element

String Formatting in java to replace the array index with the pointed string element


By : Amol Shirude
Date : March 29 2020, 07:55 AM
around this issue We have to replace as follows Alibaba site china comparison best-Replacement array {} is {4} online {3} shopping {} in {}-positional argument array , You can use MessageFormat like this
code :
public static void main(String args[]) throws Exception{
    String result = MessageFormat.format("{0} is {4} online {3} shopping {1} in {2}" ,
            "Alibaba" ,"site",  "china", "comparison", "best");
    System.out.println(result);
}
Alibaba is best online comparison shopping site in china
Dotnet Core - Getting a warning on 'string.Replace(string, string?)' saying use 'string.Replace(string, string?, System.

Dotnet Core - Getting a warning on 'string.Replace(string, string?)' saying use 'string.Replace(string, string?, System.


By : Tony
Date : March 29 2020, 07:55 AM
this will help just... tell it what comparison type you want; for example, for an ordinal-ignore-case replace:
code :
    .Replace("and", "&", StringComparison.OrdinalIgnoreCase)
    .Replace("substringof", string.Empty, StringComparison.OrdinalIgnoreCase)
    .Replace("(", string.Empty, StringComparison.OrdinalIgnoreCase)
    .Replace(")", string.Empty, StringComparison.OrdinalIgnoreCase)
    .Replace("'", string.Empty, StringComparison.OrdinalIgnoreCase)
    .Replace(" ", string.Empty, StringComparison.OrdinalIgnoreCase)
    .Replace("eq", ",", StringComparison.OrdinalIgnoreCase);
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