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What does the new keyword do here?


What does the new keyword do here?

By : Dtaivpp
Date : November 21 2020, 09:01 AM
I wish did fix the issue. new my_class() creates a new object of type my_class. It is not assigned; so it is discarded.
But before being discarded, the object is built anyway; the constructor is run and prints its object's a attribute value. 8.
code :


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Regex Python - Find every keyword instance, extract keyword and proceeding characters

Regex Python - Find every keyword instance, extract keyword and proceeding characters


By : user3127628
Date : March 29 2020, 07:55 AM
around this issue Using the "DOI variations" DOI|DO1|D01|D0I|001|00I|0O1|0OI|O01|O0I|OO1|OOI literally in that form is not a good idea. Start from basics: D+0+O, O+0, and I+1. This leads immediately to the pattern "[D0O][O0][I1]" which is much more compact, less error prone, and capable of much faster execution (if you wanted to get into Cython or C).
You can then IN THIS CASE use re.finditer() to find matching 3-character prefixes, and take it from there.
code :
Input text:     DODOD987654321
First match:    DODOD987654321
Second match:     DOD987654321 # Not found by re.finditer()
Is there a way to determine in which stage a keyword was executed(setup/step/teardown) inside the keyword?

Is there a way to determine in which stage a keyword was executed(setup/step/teardown) inside the keyword?


By : Bar-Levav
Date : March 29 2020, 07:55 AM
will help you Not directly. The list of automatic variables available in Robot Framework is available in the User Guide. There is no such thing as the source of the keyword call. There are many workarounds though. Either you use multiple keyword variations that call your "core" keyword, or you use an argument in your keyword (source) or a global variable. If you try and fail, share your attempt and people will try to help you.
robot test framework: Run Keyword If incurs User keyword contains no keyword

robot test framework: Run Keyword If incurs User keyword contains no keyword


By : CLog
Date : March 29 2020, 07:55 AM
help you fix your problem It turned out that in the definition of Enable Laser, the [Documentation] needs to be indented.
like this:
code :
Enable Laser    [Arguments]     ${app_id}   ${status}
    [Documentation]     Turn on or off laser and then check Signal Sync Link. ${status} should be all upper case
    ${commmand}    Catenate    SEPARATOR=    ${app_id}    .0.SignalTx.LaserEnable
    send cmd    ${app_id}    a_goto_state    ${commmand}    ${status}
When unpacking a dictionary to pass as keyword arguments, how can I map a key to a differently named keyword argument?

When unpacking a dictionary to pass as keyword arguments, how can I map a key to a differently named keyword argument?


By : Lucky
Date : March 29 2020, 07:55 AM
To fix the issue you can do Let's say I have some code: , Remove key c and add b:
code :
def test(a, b, **kwargs):
    print(kwargs)

l = {'a': 0, 'c': 1, 'foo': 2, 'bar': 3}

l2 = l.copy()
l2['b'] = l2['c']
del l2['c']

test(**l2)
{'foo': 2, 'bar': 3}
BigQuery , Union issue / Error: Syntax error: Expected keyword ALL or keyword DISTINCT but got keyword SELECT at [16:3]

BigQuery , Union issue / Error: Syntax error: Expected keyword ALL or keyword DISTINCT but got keyword SELECT at [16:3]


By : sambhu
Date : March 29 2020, 07:55 AM
like below fixes the issue Currently, I'm trying to connect 4 tables together and display only 5 columns and union them all to one table. , Answer:
1) For Big Query have to use UNION ALL instead of UNION
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