PHP shortcut for if stament

PHP shortcut for if stament

By : Shannon Blake
Date : November 21 2020, 09:01 AM
Does that help This is called Ternary Operator
The way you use it often start with a language construct, variable assignment, or just plain expression statement.
code :

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Android - Pick shortcut - I get shortcut intent and title but can't get shortcut icon

Android - Pick shortcut - I get shortcut intent and title but can't get shortcut icon

By : KDG
Date : March 29 2020, 07:55 AM
Does that help You was almost there.
Intent.EXTRA_SHORTCUT_ICON should be a pacelled Bitmap, not a String.
When I create shortcut (B) to another shortcut (A) its taking path of Shortcut A

When I create shortcut (B) to another shortcut (A) its taking path of Shortcut A

Date : March 29 2020, 07:55 AM
Does that help Despite what I wrote in an earlier comment, apparently creating a shortcut to a shortcut is programmatically possible starting in Windows 7 by using the SLDF_ALLOW_LINK_TO_LINK flag with IShellLinkDataList::SetFlags.
if else stament in php

if else stament in php

By : Jesper J
Date : March 29 2020, 07:55 AM
I wish this helpful for you
Your Variable $row within your Conditional Check Block if($row[0] > 0) { was not yet defined at the Point where it was used. In other words; the entire Conditional Logic should be moved into the while Loop Construct...
code :


    $con    = mysqli_connect(HOST,USER,PASS,DB);
    $month  = 10;
    $year   = 2016;
    $result = array();
    | $month  = $_POST['month']; |
    | $year   = $_POST['year'];  |

    for($day=1; $day<=31; $day++) {
        $sql    = " SELECT COUNT(entryID) ";
        $sql   .= " FROM Entry WHERE ";
        $sql   .= " EXTRACT( DAY FROM(entryTime) )      = '$day'   ";
        $sql   .= " AND EXTRACT(MONTH FROM(entryTime))  = '$month' ";
        $sql   .= " AND EXTRACT(YEAR FROM(entryTime))   = '$year'  ";
        $res    = mysqli_query($con,$sql);  

        while($row = mysqli_fetch_array($res)) {
            if($row[0] > 0) {        //<== CONDITIONAL LOGIC HERE, INSTEAD
                $day2 = (string)$day;
                    array('day'     => $day2,
                          'count'   => $row[0]

    echo $appear . json_encode(array("result"=>$result));   
Char and if stament in C

Char and if stament in C

By : akash verma
Date : March 29 2020, 07:55 AM
will help you start is an array of pointers to char and you probably want an array of char. So change
how to make an if in a AWK stament

how to make an if in a AWK stament

By : Sensiblefolk
Date : September 25 2020, 09:00 PM
I think the issue was by ths following , You need to put ; between statements, and if you have multiple statements in an if or else block you need to wrap them in curly braces.
code :
awk '{if ($2 == $4) {$1=$1+$3; print $1" "$2} else print $1" "$2}'
awk '$2 == $4 { $1 = $1 + $3 } {print $1" "$2}'
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