What is the pythonic way of doing nothing?

What is the pythonic way of doing nothing?

By : Tim Harper
Date : November 22 2020, 09:00 AM
I hope this helps . If you would like to wait for the thread to exit, use thread.join():
code :
import threading
t = threading.Thread(name='non-daemon', target=non_daemon)

t.start() # This will not block
t.join() #  This is blocking

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A more pythonic way

A more pythonic way

By : aleksandar
Date : March 29 2020, 07:55 AM
will be helpful for those in need Is there any better way to write this function? , Very simple:
code :
def highest_strength(graph):
    return max((s, x, y) for x, links in graph.items() for y, s in links.items())
>>> highest_strength(graph)
(4, 'c', 'b')
def highest_strength(G):
    best_strength, best_link = None, (None, None)
    for x, links in G.items():
        for y, v in links.items():
            if v > best_strength:
                best_strength, best_link = v, (x, y)
    return best_link
Pythonic way of doing so?

Pythonic way of doing so?

By : Redoxo
Date : March 29 2020, 07:55 AM
wish help you to fix your issue I wish to have the following simple algorithm implemented in Python. Here is the pseudo-code for it.
code :
return random.choice(filter(myCondition, myList) or myList)
What does pythonic mean?

What does pythonic mean?

By : Isael
Date : March 29 2020, 07:55 AM
wish helps you Exploiting the features of the Python language to produce code that is clear, concise and maintainable.
Pythonic means code that doesn't just get the syntax right but that follows the conventions of the Python community and uses the language in the way it is intended to be used.
code :
for i in (i; i < items.length ; i++)
  n = items[i];
 ... now do something
for i in items:
(i.some_attribute for i in items)
What is the Pythonic way of doing this?

What is the Pythonic way of doing this?

By : user3851673
Date : March 29 2020, 07:55 AM
it should still fix some issue I want a list of dicts for some data, I tried doing it this way: , Should you really want a one-liner:
code :
>>> dataList = ['Jim    5656    qwgh', 'Tim    5833    qwgh']
>>> [dict(zip(['name', 'sknum'], s.split())) for s in dataList]
[{'name': 'Jim', 'sknum': '5656'}, {'name': 'Tim', 'sknum': '5833'}]
Which of these is pythonic? and Pythonic vs. Speed

Which of these is pythonic? and Pythonic vs. Speed

By : Zhang Ben
Date : March 29 2020, 07:55 AM
it helps some times You seem to create a lot of lambdas every time you parse. You really don't need a lambda, just a multiplier. Try this:
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