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Printing a Stream in Elixir


Printing a Stream in Elixir

By : Leonardo Tumadjian
Date : November 22 2020, 09:00 AM
To fix this issue You need explicit parentheses for your Stream.reject function. See Why Can't I Chain String.replace? for a detailed explanation.
code :
File.stream!("foobar") |> Stream.reject(digits) |> Enum.each(&IO.write/1)


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Printing to Console from Elixir Process

Printing to Console from Elixir Process


By : heshamkadry
Date : March 29 2020, 07:55 AM
wish help you to fix your issue So, I started playing around with Elixir, and I wanted to make two modules. One that would prompt you to enter a message, and then send the message to the other program which would acknowledge that it got the message, which would cause the first program to print out the message. , The first problem is:
code :
pid = :erlang.spawn(&PracticeServer.start/0)
pid = :erlang.spawn(&PracticeServer.start/0)
pid = PracticeServer.start
Enter a message:hello
Thank you for your message!
Enter a message:world
Thank you for your message!
Enter a message:kill
Thank you for your message!
message = IO.gets "Enter a message:"
message = IO.gets("Enter a message:") |> String.trim_trailing
Enter a message:kill
Process Dead
Enter a message:kill
Process Dead
defmodule PracticeCaller do
  def start do
    spawn(fn -> loop(PracticeServer.start) end)
  end

  def loop(server) do
    message = IO.gets("Enter a message: ") |> String.trim_trailing
    send(server, {self, message})
    receive do
      {_caller, reply} ->
        IO.puts "#{reply}"
        # Only continue if process is not dead.
        # Comparing against strings is usually not idiomatic, you may want to
        # change that.
        if reply != "Process Dead" do
          loop(server)
        end
    end
  end
end

defmodule PracticeServer do
  def start do
    spawn(&loop/0)
  end

  def loop do
    receive do
      {caller, "kill"} ->
        send(caller, {self, "Process Dead"})
      {caller, _} ->
        send(caller, {self, "Thank you for your message!"})      
        loop    
    end
  end
end

PracticeCaller.start
:timer.sleep(:infinity)
Elixir: Printing list along with string

Elixir: Printing list along with string


By : Elias Alves Chacon
Date : March 29 2020, 07:55 AM
Does that help Starting with Elixir 1.4, IO.inspect/2 accepts label option among others:
code :
IO.inspect list, label: "The list is"
#⇒ The list is: [1, 2, 3]
Printing integer in hexadecimal with Elixir

Printing integer in hexadecimal with Elixir


By : Revictus
Date : March 29 2020, 07:55 AM
With these it helps I can do this in Erlang: , Adding @Dogbert's comment as an answer:
Try using single quotes:
code :
:io.fwrite('~.16X~n', [-31, '0x'])
Elixir: Correct way of printing __STACKTRACE__

Elixir: Correct way of printing __STACKTRACE__


By : SangramKBehera
Date : March 29 2020, 07:55 AM
I hope this helps you . Just the Stacktrace
This was answered by Michał Muskała on the official elixir github issue:
code :
Logger.error(Exception.format_stacktrace())
def unreliable_method do
  # do something
  :ok
rescue
  err ->
    Logger.error(Exception.format(:error, err, __STACKTRACE__))
    {:error, :processing_failed}
end
How to take an element of a stream (Elixir) and keep the state of the stream?

How to take an element of a stream (Elixir) and keep the state of the stream?


By : skimo
Date : March 29 2020, 07:55 AM
I wish this helpful for you TL;DR Save the accumulator, not “Stream.”
The robust solution is provided by @Dogbert in comments: StreamSplit package seems to permorm exactly what was asked.
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