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Regex not matching regex in PHP


Regex not matching regex in PHP

By : FOSSMandala
Date : November 22 2020, 09:00 AM
I think the issue was by ths following , I am currently working at a project involving regex in php. I wanted to know why or how can I get this recursive regular expression to work in PHP: , Why this complex?
code :
preg_match ('/\:"\((.*)\)"/', $search, $ matches);


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regex with negative matching (ie, find string that _doesn't_ match regex)

regex with negative matching (ie, find string that _doesn't_ match regex)


By : Kevin Valmonte
Date : March 29 2020, 07:55 AM
it helps some times I have a log file with the string "ERROR" on some lines. I want to delete every line that doesn't have ERROR so that I can see just what needs fixing. I was going to do something like the following in vim: , Use the :g! command to delete every line that doesn't match.
code :
:g!/ERROR/d
How to make a perl regex and references part of the matching string in the regex?

How to make a perl regex and references part of the matching string in the regex?


By : Nestor
Date : March 29 2020, 07:55 AM
Hope this helps I would probably use a match to breakup the string, and then reassemble it a line later:
code :
$sample =~ /(.*?)[+\-]([0-9])([a-zA-Z]+)(.*)/ ;
$sample= $1 . substr($3, $2) . $4 if $2 ;
Why isn't `regex!` a wrapper for `Regex::new` to offer the same regex matching speed?

Why isn't `regex!` a wrapper for `Regex::new` to offer the same regex matching speed?


By : Jacob M
Date : March 29 2020, 07:55 AM
fixed the issue. Will look into that further The answer is very subtle: one feature of the macro is that the result of regex! can be put into static data, like so:
code :
static r: Regex = regex!("t?rust");
Matching user entered input with regex and trimming the invalid inputs to match regex

Matching user entered input with regex and trimming the invalid inputs to match regex


By : Andreia Silva
Date : March 29 2020, 07:55 AM
help you fix your problem Use this regex to find multiple consecutive occurrences of / and replace it with just one /
code :
const res = " PVER : abc //// def ; 0".replace(/(\/)\1+/g, "/");

console.log(res);
const res = "PVER : abc //// def ; 0".match(/^PVER : [a-z|A-Z|0-9|_]* [/]+ [a-z|A-Z|0-9|_]* ; 0$/g);

console.log(res);
Python regex: How to implement a regex expression that checks for matching set of brackets?

Python regex: How to implement a regex expression that checks for matching set of brackets?


By : user3418922
Date : March 29 2020, 07:55 AM
around this issue If your brackets are not nested and not escaped then you can use this regex to validate your input:
code :
^(?:[^{}]*{[^}]*})*[^{}]*$
^(?!$)(?:[^{}]*{[^}]*})*[^{}]*$
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