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Find a word preceding a symbol set


Find a word preceding a symbol set

By : Nishant Motam
Date : November 22 2020, 09:00 AM
I wish this helpful for you How can I find a word that preceding to [¹²³⁴⁵⁶⁷⁸⁹⁰]. For ex.: , This will match your examples.
Codepoints:
code :
 (?:
      \b 
      # Required - Words
      \w+ 
      # Optional - Not words, nor supersctipt
      [^\w\x{B9}\x{B2}\x{B3}\x{2074}\x{2075}\x{2076}\x{2077}\x{2078}\x{2079}\x{2070}]* 

   |  # or,

      # Required - Not words, nor supersctipt
      [^\w\x{B9}\x{B2}\x{B3}\x{2074}\x{2075}\x{2076}\x{2077}\x{2078}\x{2079}\x{2070}]+ 
 )
 # Required - Superscript
 [\x{B9}\x{B2}\x{B3}\x{2074}\x{2075}\x{2076}\x{2077}\x{2078}\x{2079}\x{2070}]+ 


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Find a word NOT preceded by a specific symbol and do NOT highlight anything before this word

Find a word NOT preceded by a specific symbol and do NOT highlight anything before this word


By : Oguzhan karacar
Date : March 29 2020, 07:55 AM
it should still fix some issue This task is driving me nuts. , This should do the trick:
code :
(?<=[^!])IsPlayerRcon
Find the average length of the preceding word of another word in a string of text

Find the average length of the preceding word of another word in a string of text


By : Will Hickey
Date : March 29 2020, 07:55 AM
I hope this helps . This solution uses a dictionary, which values are lists of the lengths of all preceding words. The given example print the solution for word the (last line).
In case you are not familiar with defaultdict take a look here.
code :
from collections import defaultdict

def  prevword_ave_len(word, text):

    words = defaultdict(list)    #initialization of default dictionary

    textlist = text.split()      #split text into words
    words[textlist[0]].append(0) #append 0 for first word in text
    #iterate over words, append length of preceding word to values
    for i in range(1,len(textlist)):
        words[textlist[i]].append(len(textlist[i-1]))

    if word in words:
        return sum(words[word])/len(words[word])    #calculate mean
    else: return False

if __name__ == "__main__":

    text = "Call me Ishmael. Some years ago - never mind how long precisely - having little or no money in my purse, and nothing particular to interest me on shore, I thought I would sail about a little and see the watery part of the world. It is a way I have of driving off the spleen and regulating the circulation. Whenever I find myself growing grim about the mouth; whenever it is a damp, drizzly November in my soul; whenever I find myself involuntarily pausing before coffin warehouses, and bringing up the rear of every funeral I meet; and especially whenever my hypos get such an upper hand of me, that it requires a strong moral principle to prevent me from deliberately stepping into the street, and methodically knocking people's hats off - then, I account it high time to get to sea as soon as I can. This is my substitute for pistol and ball. With a philosophical flourish Cato throws himself upon his sword; I quietly take to the ship. There is nothing surprising in this. If they but knew it, almost all men in their degree, some time or other, cherish very nearly the same feelings towards the ocean with me."

    print(prevword_ave_len('the', text))
Regex - Find biggest possible match, which would have been found without preceding word checking, or nothing

Regex - Find biggest possible match, which would have been found without preceding word checking, or nothing


By : prg andr
Date : March 29 2020, 07:55 AM
seems to work fine I do not know the exact terminology and therefore could unfortunately not find a solution for my particular case. , The regex
code :
(?<=[^,\d]\s|^)(\d+(?:\d+\s*)+)
Javascript regex to find a pattern in a string, excluding a possible preceding word match

Javascript regex to find a pattern in a string, excluding a possible preceding word match


By : T.Linker
Date : March 29 2020, 07:55 AM
like below fixes the issue There is a string of writing/text in a variable: , You can try this :
code :
(?:\b)(?!let)(?=\w+\sfirst_name\s+(know|keep|enjoy))(\w+ \w+)\s+(\w+)
const regex = /(?:\b)(?!let)(?=\w+\sfirst_name\s+(know|keep|enjoy))(\w+ \w+)\s+(\w+)/g;
const str = `One of the reasons first_name keep waking up at night, is blah blah blah. Try this, let first_name know and see blah blah blah. Remember that first_name enjoy being challenged and blah blah blah`;
const subst = `$2 _object_s`;

const result = str.replace(regex, subst);
console.log(result);
Excel: find a word in a cell, then return the preceding word and the found word

Excel: find a word in a cell, then return the preceding word and the found word


By : David King
Date : March 29 2020, 07:55 AM
I hope this helps you . This is a slightly different take on a previous question I asked. I tried to modify the great advice I received but couldn't quite get there.
code :
=TRIM(RIGHT(SUBSTITUTE(LEFT(B2,SEARCH(" Truck ",B2)+5)," ",REPT(" ",99)),199))
This                                                                                                   is                                                                                                   a                                                                                                   test                                                                                                   dump                                                                                                   TRUCK
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