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List sorting in Python (transpose)


List sorting in Python (transpose)

By : underwater-smiles
Date : November 22 2020, 09:00 AM
hope this fix your issue You can use zip_longest
code :
>>> from itertools import zip_longest
>>> a = [1,1]
>>> b = [2]
>>> c = [3,3,3]
>>> f,g,h=[[e for e in li if e is not None] for li in zip_longest(a,b,c)]
>>> f
[1, 2, 3]
>>> g
[1, 3]
>>> h
[3]
>>> b = [None]
>>> sentinel = object()
>>> [[e for e in li if e is not sentinel] for li in zip_longest(a,b,c, fillvalue=sentinel)]
[[1, None, 3], [1, 3], [3]]


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Python list transpose and fill

Python list transpose and fill


By : ek9
Date : March 29 2020, 07:55 AM
like below fixes the issue I have a list of lists such that the length of each inner list is either 1 or n (assume n > 1). , You can repeat one element list forever:
code :
uneven = [[1], [47, 17, 2, 3], [3], [12, 5, 75, 33]]

from itertools import repeat

print zip(*(repeat(*x) if len(x)==1 else x for x in uneven))
Transpose nested list in python

Transpose nested list in python


By : Poornima Sivakumar
Date : March 29 2020, 07:55 AM
With these it helps I like to move each item in this list to another nested list could someone help me? , Use zip with * and map:
code :
>>> map(list, zip(*a))
[['AAA', 'BBB', 'CCC', 'DDD', 'EEE', 'FFF', 'GGG', 'HHH', 'III'],
 ['1', '262', '86', '48', '8', '39', '170', '16', '4'],
 ['1', '56', '84', '362', '33', '82', '296', '40', '3'],
 ['10', '238', '149', '205', '96', '89', '223', '65', '5'],
 ['92', '142', '30', '237', '336', '140', '210', '50', '2']]
[list(x) for x in zip(*a)]
>>> import numpy as np
>>> np.array(a).T.tolist()
[['AAA', 'BBB', 'CCC', 'DDD', 'EEE', 'FFF', 'GGG', 'HHH', 'III'],
 ['1', '262', '86', '48', '8', '39', '170', '16', '4'],
 ['1', '56', '84', '362', '33', '82', '296', '40', '3'],
 ['10', '238', '149', '205', '96', '89', '223', '65', '5'],
 ['92', '142', '30', '237', '336', '140', '210', '50', '2']]
Lazily transpose a list in Python

Lazily transpose a list in Python


By : Alan Pretty
Date : March 29 2020, 07:55 AM
I hope this helps you . Your transpose is pretty much exactly what you need.
With any solution you'd choose, you'd have to buffer the unused values (e.g. to get to the 7, you have to read 1-6, and store them in memory for when the other iterables ask for them). tee already does exactly that kind of buffering, so there's no need implementing it yourself.
code :
def transpose(iterable_of_three_tuples):
    teed = itertools.tee(iterable_of_three_tuples, 3)
    return ( e[0] for e in teed[0] ),  ( e[1] for e in teed[1] ),  ( e[2] for e in teed[2] )
How to transpose a 3D list in python?

How to transpose a 3D list in python?


By : Kristina Aleshnikova
Date : March 29 2020, 07:55 AM
Any of those help Let's say I have this matrix m of dimensions 9 x 9 x 26: , If you have a list and not a numpy array:
code :
m = [[['a00',  'z00'], ['a01',  'z01'],  ['a09',  'z09']],
[['a10',  'z10'], ['a11',  'z11'],  ['a19',  'z19']],   
[['a90',  'z90'], ['a91',  'z91'],  ['a99',  'z99']]]

from itertools import chain
print zip(*(chain(*m))

[('a00', 'a01', 'a09', 'a10', 'a11', 'a19', 'a90', 'a91', 'a99'), 
('z00', 'z01', 'z09', 'z10', 'z11', 'z19', 'z90', 'z91', 'z99')]
Python: How to apply sorting (by max value) of one list to element index sorting of another list

Python: How to apply sorting (by max value) of one list to element index sorting of another list


By : masq.zephyr
Date : March 29 2020, 07:55 AM
I wish this help you e.g. , You can take advantage of the pandas library like so
code :
import pandas as pd

# before
lst1=['1','3','2','4']
lst2=['100','5000','999','666']

# Use pandas
df = pd.DataFrame({'A':lst1,'B':lst2}).sort_values('A', ascending =False)

# After
lst1 = df['A'].tolist()
lst2 = df['B'].tolist()
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