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Php method not being called


Php method not being called

By : user67987
Date : November 22 2020, 02:42 PM
this will help I have been trying to debug this code for a while now, and it looks like the build method is not being called. I put echo's, var_dumps, and all other kinds of signs in it, but never get anything. , Fix and update the code bellow:
Constructor:
code :


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Should a modifying class method save itself or be explicity called after the method is called?

Should a modifying class method save itself or be explicity called after the method is called?


By : user2094033
Date : March 29 2020, 07:55 AM
fixed the issue. Will look into that further The user of your API might forget to call .save() and then get screwed. So I think its better to call save for him. For cases like those Daslch mentions, if it makes sense, you can define:
code :
def set_foo(self, foo, skip_save=False):
    self.foo = foo
    if not skip_save:
        self.save()
How can I create a method that gets called every time a public method gets called?

How can I create a method that gets called every time a public method gets called?


By : K.R.
Date : March 29 2020, 07:55 AM
To fix this issue Might not be what you expect or want exactly, but by using the magic method __call and marking those public methods protected or private you can get the desired effect:
code :
<?php
class Name {
    public function __call($method, $params) {
        if(!in_array($method, array('foo', 'bar')))
            return;
        $this->baz();
        return call_user_func_array(
                    array($this, $method), $params);
    }

   protected function foo() {
      echo "Foo called\n";
   }

   protected function bar() {
      echo "Bar called\n";
   }

   protected function baz() {
      echo "Baz called\n";
   }
}

$name = new Name();
$name->foo();
$name->bar();
How to automatically call a another method in a class with result of the called method when a method is called?

How to automatically call a another method in a class with result of the called method when a method is called?


By : Davide F
Date : March 29 2020, 07:55 AM
Any of those help I have a class with few methods like this.. , You can just call the function inside the other function:
code :
$ret = false;
// return true or false
if (!$ret) $this->ifFalse();
return $ret;
public function __call($name, $arguments)
{
    switch($name) {
        case 'funcA':
        case 'funcB':
            $value = $this->$name(...$arguments);
            if (!$value) $this->ifFalse();
            return $value;
        break;
    }
}

private function funcA(arguments) : bool
{
    // return true or false
}

private function funcB(arguments) : bool
{
    // return true or false
}
Bad state: Mock method was not called within `when()`. Was a real method called?

Bad state: Mock method was not called within `when()`. Was a real method called?


By : user2596135
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , This issue may happen when you implement a method you want to mock instead of letting Mockito do that.
This code below will return Bad state: Mock method was not called within when(). Was a real method called?:
code :
class MockFirebaseAuth extends Mock implements FirebaseAuth {
  FirebaseUser _currentUser;

  MockFirebaseAuth(this._currentUser);

  // This method causes the issue.
  Future<FirebaseUser> currentUser() async {
    return _currentUser;
  }
}

final user = MockFirebaseUser();
final mockFirebaseAuth = MockFirebaseAuth(user);

// Will throw `Bad state: Mock method was not called within `when()`. Was a real method called?`
when(mockFirebaseAuth.currentUser())
    .thenAnswer((_) => Future.value(user));
class MockFirebaseAuth extends Mock implements FirebaseAuth {}

final user = MockFirebaseUser();
final mockFirebaseAuth = MockFirebaseAuth();

// Will work as expected
when(mockFirebaseAuth.currentUser())
    .thenAnswer((_) => Future.value(user));
class MyClass {
  String doSomething() {
    return 'test';
  }
}

final myClassInstance = MyClass();

// Will throw `Bad state: Mock method was not called within `when()`. Was a real method called?`
when(myClassInstance.doSomething())
    .thenReturn((_) => 'mockedValue');
Can you require a separate method be called when a static method is called?

Can you require a separate method be called when a static method is called?


By : Ankit
Date : March 29 2020, 07:55 AM
Hope that helps If you want to check a condition every time a method is run, then this is really the only practical way to do it.
Even if you made all the methods non-static, the constructor would only be called once, and the methods would be free to run without the condition check if the check was satisfied at the instantiation of the object.
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