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string -- x y in REGEX


string -- x y in REGEX

By : Bayan Bennett
Date : November 22 2020, 02:42 PM
To fix this issue Quick question. I have this string
code :
string -- ([1-9]\d{0,2}) ([1-9]\d{0,2})
string --  matches the characters string --  literally (case sensitive)
1st Capturing group ([1-9]\d{0,2})
    [1-9] match a single character present in the list below
        1-9 a single character in the range between 1 and 9
    \d{0,2} match a digit [0-9]
        Quantifier: {0,2} Between 0 and 2 times, as many times as possible, giving back as needed [greedy]
      matches the character   literally
2nd Capturing group ([1-9]\d{0,2})
    [1-9] match a single character present in the list below
        1-9 a single character in the range between 1 and 9
    \d{0,2} match a digit [0-9]
        Quantifier: {0,2} Between 0 and 2 times, as many times as possible, giving back as needed [greedy]
string -- 1 999 //matches
string -- 10 02 //does not match
string -- 011 222 //does not match
string -- 111 222 //matches
string -- 41 2 //matches
string -- 999 1 //matches
string -- 1 1 //matches


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Check the end of a string for valid regex and return the string trimmed of the regex-

Check the end of a string for valid regex and return the string trimmed of the regex-


By : Sneha
Date : March 29 2020, 07:55 AM
hop of those help? Here is an attempt to explain a bit clearer with code-- , You should simply replace:
code :
str = 'testfoostringfoo';
var regex = /foo$/;
str = str.replace(regex, '');
return str;
How to interpolate a regex into string and use that string as regex to compare in ruby

How to interpolate a regex into string and use that string as regex to compare in ruby


By : Moses Maghas
Date : March 29 2020, 07:55 AM
will be helpful for those in need I assume that foo contains a string, which represents the regexp. If so, you can initialize Regexp object from that string and perform your matching as follows:
code :
foo = 'test.*check.*code'

goo =~ Regexp.new(foo, Regexp::MULTILINE)
I want to do String.replaceAll(regex, regex) instead of (regex, String) in Java

I want to do String.replaceAll(regex, regex) instead of (regex, String) in Java


By : tom shech
Date : March 29 2020, 07:55 AM
like below fixes the issue Since Java 9 Matcher class contains replaceAll​(Function replacer) where you can specify dynamically what should be used as replacement based on current match. So your code may look like:
code :
Map<String, String> replacementsMap = Map.ofEntries(
        Map.entry("1", "N"),
        Map.entry("N", "1")
);

String input = "10N10N";
Pattern p = Pattern.compile("1|N");
Matcher m = p.matcher(input);
String replaced = m.replaceAll(match -> replacementsMap.get(match.group()));
System.out.println(replaced);
//create Pattern p, Matcher m and replacement map
StringBuffer sb = new StringBuffer();
while(m.find()){
    m.appendReplacement(sb, replacementsMap.get(m.group()));
}
m.appendTail(sb);
String replaced = sb.toString();
String input = "10N10N";
String replaced = StringUtils.replaceEach(input, new String[] {"1","N"}, new String[] {"N","1"});
System.out.println(replaced);//N01N01
Does C# have a natural way to check regex match for single string and multiple regex, with single pass through string?

Does C# have a natural way to check regex match for single string and multiple regex, with single pass through string?


By : Mohammed Islam
Date : March 29 2020, 07:55 AM
I wish did fix the issue. Let's say I have a collection of regexes , You can use matching groups in Regex along with OR:
code :
(abc)|(ghi)
How to make the regex from .replaceAll(String regex, String replacement) safe for Userinput?

How to make the regex from .replaceAll(String regex, String replacement) safe for Userinput?


By : abcdef
Date : March 29 2020, 07:55 AM
will be helpful for those in need If you don't want the user's text to be interpreted as a regex, just use replace instead of replaceAll.
code :
String str = "foo bar [] baz []";
String userInput = "[]";
String replacement = "moo";
str = str.replace(userInput, replacement);
// str = "foo bar moo baz moo"
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