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rename the header of the spliting group in r


rename the header of the spliting group in r

By : Hazem-alhakam
Date : November 22 2020, 02:42 PM
it should still fix some issue Im wondering how to change the header name of splitted group. , We can use setNames
code :
setNames(d1, c('Tom', 'Jerry', 'Jane'))
colnames(d1) <- c('Tom', 'Jerry', 'Jane')


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preg_match spliting one word in two, returning last character as a captured group

preg_match spliting one word in two, returning last character as a captured group


By : I'Art Atm
Date : March 29 2020, 07:55 AM
like below fixes the issue That is because you require at least one letter in the second [a-zA-Z]+. If you make that second capturing group optional it should work:
code :
/^([a-zA-Z]+)(?:[,]?[\s]?)?([a-zA-Z]+)?((?:\s)([a-zA-Z]{1}))?$/i
/^([a-z]+)(?:,?\s?)?([a-z]+)?((?:\s)([a-z]))?$/i
/^([a-z]+)(?:(?:,\s?|\s)([a-z]+)?)?(?:\s([a-z]))?$/i
How to create a group by spliting the dataframe using python

How to create a group by spliting the dataframe using python


By : Bri
Date : March 29 2020, 07:55 AM
To fix this issue My dataframe: , Your data:
code :
df = pd.DataFrame({'order':['A', 'B', 'C', 'D', 'E', 'F'],'quantity':[1,1,2,3,3,4]})
df = pd.DataFrame(np.concatenate(df.apply(lambda x: [x[0]] * x[1], 1).as_matrix()), 
                  columns=['order'])
df['quantity'] = 1
df['group'] = sorted(range(0, len(df)/3, 1) * 4)[0:len(df)]
   order  quantity  group
0      A         1      0
1      B         1      0
2      C         1      0
3      C         1      0
4      D         1      1
5      D         1      1
6      D         1      1
7      E         1      1
8      E         1      2
9      E         1      2
10     F         1      2
11     F         1      2
12     F         1      3
13     F         1      3
df.groupby(['group', 'order']).sum()
             quantity
group order          
0     A             1
      B             1
      C             2
1     D             3
      E             1
2     E             2
      F             2
3     F             2
Spliting GROUP BY results into different columns

Spliting GROUP BY results into different columns


By : john324156
Date : March 29 2020, 07:55 AM
this will help You have additional columns in the result set that are not in the query. However, this should work:
code :
SELECT ID_HR,
       max(case when rn = 1 then DIAS_DUR end) as DIAS_DUR1,
       max(case when rn = 1 then INI end) as INI1,
       max(case when rn = 1 then FIN end) as FIN1,

       max(case when rn = 2 then DIAS_DUR end) as DIAS_DUR2,
       max(case when rn = 2 then INI end) as INI2,
       max(case when rn = 2 then FIN end) as FIN2,

       max(case when rn = 3 then DIAS_DUR end) as DIAS_DUR3,
       max(case when rn = 3 then INI end) as INI3,
       max(case when rn = 3 then FIN end) as FIN3
FROM CTE
GROUP BY ID_HR;
Some questions of tile group header template - get value of group header, change automatically group header at editing

Some questions of tile group header template - get value of group header, change automatically group header at editing


By : Mostafijur
Date : March 29 2020, 07:55 AM
Any of those help I answer my questions :
1) it's TemplateBinding Content to get the value
code :
<devexpress:TileLayoutControl.GroupHeaderTemplate>
                <DataTemplate>
                    <local:EditableTextBoxHeader Texte="{TemplateBinding Content}" TexteColor="Black" FontSize="{StaticResource TaillePoliceGrande}" FontWeight="Bold"/>
                </DataTemplate>      
</devexpress:TileLayoutControl.GroupHeaderTemplate>
How to localize/rename the "Default" (no group) header in a Winforms ListView?

How to localize/rename the "Default" (no group) header in a Winforms ListView?


By : MSaavedra
Date : March 29 2020, 07:55 AM
will be helpful for those in need wondering if anyone can help with a Windows Forms/.net ListView issue (using C# in this case...) , here is what documentation says
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