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XOR of two strings of 0s and 1s


XOR of two strings of 0s and 1s

By : audrey goeson
Date : November 22 2020, 02:42 PM
Any of those help No. You can't simply XOR two strings like this str1 ^ str2 (^ is not overloaded for strings to do this).
Iterate over the strings and XOR the chars step by step. You will even need to 'implement the XOR on chars' yourself (since ^ is a bit-wise XOR which is not what you want judging from your sample).
code :


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Easy way to concatenate list of strings into a comma-separated strings, where strings are members of an object?

Easy way to concatenate list of strings into a comma-separated strings, where strings are members of an object?


By : moogheads
Date : March 29 2020, 07:55 AM
wish helps you Say I have a List(Of Tag) with Tag being an object. One member of Tag, Tag.Description, is a string, and I want to make a comma-separated concatenation of the Description members. , Try this:
code :
String.Join(", ", tagList.Select(t => t.Description).ToArray());
ORDER BY strings (can be numbers or strings) putting empty strings last MySQL

ORDER BY strings (can be numbers or strings) putting empty strings last MySQL


By : Nicolas
Date : March 29 2020, 07:55 AM
should help you out I have a problem ordering a table.
code :
order by 
case 
when column is null then 1 else 0 
end, 
column
  ORDER BY ISNULL(column), column ASC;
  ORDER BY if(column = '' or column is null,1,0),column
Get an Array or List of Strings between some Strings (Search multiple Strings)

Get an Array or List of Strings between some Strings (Search multiple Strings)


By : user3495527
Date : March 29 2020, 07:55 AM
To fix this issue If you have to parse an XML file, I suggest you to use XPath language. So you have to do basically these actions:
Parse the XML String inside a DOM object Create an XPath query Query the DOM
code :
String xml = ...;
try {
   // Build structures to parse the String
   DocumentBuilder builder = DocumentBuilderFactory.newInstance().newDocumentBuilder();
   // Parse the XML string into a DOM object
   Document document= builder.parse(new ByteArrayInputStream(xml.getBytes()));
   // Create an XPath query
   XPath xPath =  XPathFactory.newInstance().newXPath();
   // Query the DOM object with the query '//hello'
   NodeList nodeList = (NodeList) xPath.compile("//hello").evaluate(document, XPathConstants.NODESET);
} catch (Exception e) {
   e.printStackTrace();
}
Difference between string, cell array of strings, vector of strings, and matrix of strings in Matlab

Difference between string, cell array of strings, vector of strings, and matrix of strings in Matlab


By : jkings52
Date : March 29 2020, 07:55 AM
should help you out You are probably being confused by not realizing that you aren't really creating an array of strings, rather, you are creating a matrix of characters.
Your string_list is a 1x14 matrix of chars: my nameis xyz! (note you are missing a space between name and is). Then within your code fprintf(fid, '%s\t', string_list(k)) is taking each element of that string and printing it with a tab character between elements, which is what you are getting.
code :
if iscellstr(string_list)
   fprintf('%s\t',string_list{:});
else
   % just a char matrix
   fprintf('%s\t',string_list);
end
string_list = ["my", " ", "name", "is", " ", "xyz!"];
if isstring(string_list)
   fprintf('%s\t',string_list)
end
I have a function returning a vector of strings. It takes two strings and is to return the strings in one that are missi

I have a function returning a vector of strings. It takes two strings and is to return the strings in one that are missi


By : fieryjack
Date : March 29 2020, 07:55 AM
Does that help Based on the name missingWords, I'm going to guess that you want to take each input string, and tokenize it into words. Then you want to create an output that contains all the words present in one that aren't present in the other.
If that's correct, we might consider something like this:
code :
std::vector<std::string> missingWords(std::string const &a, std::string const &b)
{
    std::istringstream parse_a(a);
    std::vector<std::string> words_a(std::istream_iterator<std::string>(parse_a), {});

    std::istringstream parse_b(b);
    std::vector<std::string> words_b(std::istream_iterator<std::string>(parse_b), {});

    std::sort(words_a.begin(), words_a.end());
    std::sort(words_b.begin(), words_b.end());

    std::vector<std::string> ret;
    std::set_difference(words_a.begin(), words_a.end(), 
                        words_b.begin(), words_b.end(),
                        std::back_inserter(ret));
    return ret;
}
std::vector<std::string> missingWords(std::string const &a, std::string const &b)
{
    std::istringstream parse_a(a);
    std::set<std::string> words_a(std::istream_iterator<std::string>(parse_a), {});

    std::istringstream parse_b(b);
    std::set<std::string> words_b(std::istream_iterator<std::string>(parse_b), {});

    std::vector<std::string> ret;
    std::set_difference(words_a.begin(), words_a.end(), 
                        words_b.begin(), words_b.end(),
                        std::back_inserter(ret));
    return ret;
}
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