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Removing parts of a JSON response from API


Removing parts of a JSON response from API

By : Henry Villalva
Date : November 22 2020, 02:42 PM
this will help Try to use substring:
code :
$http({method: 'GET',
   url: "http://devel.farebookings.com/api/curconversor/GBP/USD/1/"}).

   success(function(status) {
    // your code when success
    localStorage.gbpUSD = status.substring(4);
}).


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Select certain parts from last.fm JSON response in PHP

Select certain parts from last.fm JSON response in PHP


By : justutk
Date : March 29 2020, 07:55 AM
hop of those help? I am retrieving artist information from the last.fm API. Here is a sample response for U2: , Here is how you would parse json data:
PHP
code :
$decodedJson = json_decode($json);

$artist = $decodedJson->{"artist"};
$bio = $artist->{"bio"};
$summary = $bio->{"summary"};
var_dump($summary);
How can I delete parts of a JSON web response?

How can I delete parts of a JSON web response?


By : user3067540
Date : March 29 2020, 07:55 AM
around this issue The content you get back is JSON, so you can easily turn it into a Perl data structure, play with it, and even turn it back into JSON if you like. That's the point! And, it's so easy:
code :
use Mojo::UserAgent;
use Mojo::JSON qw(decode_json encode_json);

my $ua = Mojo::UserAgent->new;

my $tx = $ua->get( 'http://ip-api.com/json/8.8.8.8' );
my $json = $tx->res->body;

my $perl = decode_json( $json );

delete $perl->{'as'};

my $new_json = encode_json( $perl );

print $new_json;
Alamofire: How to get parts of response JSON

Alamofire: How to get parts of response JSON


By : ImSanctuary
Date : March 29 2020, 07:55 AM
hope this fix your issue You can do it in Swift, but IMHO it's a lot easier using the SwiftyJSON framework. It has an excellent tutorial and documentation and you should be up an running in no time : https://github.com/SwiftyJSON/SwiftyJSON
Karate Removing different parts of JSON

Karate Removing different parts of JSON


By : user1937365
Date : March 29 2020, 07:55 AM
I wish this help you Please find below my formatted JSON Payload Dis.json , Quick Answer:
code :
Scenario: Json formatting 
    * def discountInput = read('Dis.json') 
    * def andNode = discountInput.rules.AND[1]
    * remove discountInput.rules
    * set discountInput.rules[0] = andNode
Scenario: json filter 
    * def discountInput = read('Dis.json') 
    * def filterCondition = function(x) { if(x.RULE){ return true;}} 
    * def allAND = $discountInput.rules.AND[*]
    * set discountInput.rules = karate.filter(allAND, filterCondition) 
How to filter json into specific format (removing certain parts)

How to filter json into specific format (removing certain parts)


By : danielhfrank
Date : March 29 2020, 07:55 AM
I wish this helpful for you You may try to get only these two columns in your output. Optionally, you may use MYSQLI_ASSOC constant to fetch a result row as an associative array.
code :
<?php
$rows = array();
while($r = mysqli_fetch_array($result, MYSQLI_ASSOC)) {
    $rows[] = array(
        "category" => $r["category"],
        "timestamp" => $r["timestamp"]
    );
}

$json_string = json_encode($rows, JSON_PRETTY_PRINT);
?>
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