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Create Unique Hashcode for the permutation of two Order Ids


Create Unique Hashcode for the permutation of two Order Ids

By : Mane Chakarian
Date : November 22 2020, 02:59 PM
seems to work fine You need a value that can uniquely represent every possible value.
That is different to a hash-code.
code :
public class KeyPair : IEquatable<KeyPair>
{
  public int Min { get; private set; }
  public int Max { get; private set; }

  public KeyPair(int first, int second)
  {
    if (first < second)
    {
      Min = first;
      Max = second;
    }
    else
    {
      Min = second;
      Max = first;
    }
  }

  public bool Equals(KeyPair other)
  {
    return other != null && other.Min == Min && other.Max == Max;
  }

  public override bool Equals(object other)
  {
    return Equals(other as KeyPair);
  }

  public override int GetHashCode()
  {
    return unchecked(Max * 31 + Min);
  }
}


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Unique hashCode with two fields without order

Unique hashCode with two fields without order


By : Horea Muresan
Date : March 29 2020, 07:55 AM
wish helps you You can use some sort of commutative operation instead of what you have now, like addition:
code :
@Override
public int hashCode() {
    int hash = 17;
    int hashMultiplikator = 79;
    int hashSum = first.hashCode() + second.hashCode();
    hash = hashMultiplikator * hash * hashSum;
    return hash;
}
How to overwrite the hashcode method that returns a unique hashcode value with its unique entity ID in my defined Java o

How to overwrite the hashcode method that returns a unique hashcode value with its unique entity ID in my defined Java o


By : andymahood__c
Date : March 29 2020, 07:55 AM
may help you . The easiest solution would be to rely on java.lang.Long's built-in hashCode():
code :
@Override
public int hashCode() {
    return Long.valueOf(getId()).hashCode();
}
@Override
public int hashCode() {
    return getId().hashCode();
}
How can I create a unique hashcode for a JObject?

How can I create a unique hashcode for a JObject?


By : Roman Zabolotskyi
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , You can use JTokenEqualityComparer.GetHashCode(JToken token) for this purpose. It provides access to the GetDeepHashCode() method you saw.
code :
var obj = JToken.Parse(jsonString);
var comparer = new JTokenEqualityComparer();
var hashCode = comparer.GetHashCode(obj);
setting hashcode and equals to create a set with unique object

setting hashcode and equals to create a set with unique object


By : Leonardo Romano
Date : March 29 2020, 07:55 AM
Hope that helps EDIT: I've just read your comment that you only want one letter in the entire set - which sounds like a very odd requirement, but it's basically fulfilled by something like:
Create an unique hashCode based on many values

Create an unique hashCode based on many values


By : Dominique10
Date : March 29 2020, 07:55 AM
To fix this issue It doesn't have to be unique and it cannot be unique. hashCode() returns an int (32 bits), which means it could be unique if you only had one int property and nothing else.
The Integer class can (and does) have a unique hashCode(), but few other classes do.
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