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Why are there 2 registers in ARM for enabling/disabling interrupts instead of 1?


Why are there 2 registers in ARM for enabling/disabling interrupts instead of 1?

By : xdt
Date : November 22 2020, 02:59 PM
will help you While I can't speak to the thoughts that went into the original design, my observation is that this makes it easier to ensure thread safety.
Assume there was just one register available to enable and disable interrupts; Setting a bit in the register would enable the corresponding interrupt, while clearing the bit would disable it.
code :


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what is the difference between enabling interrupts and restoring interrupts?

what is the difference between enabling interrupts and restoring interrupts?


By : oleg yakimets
Date : March 29 2020, 07:55 AM
like below fixes the issue Where excatly did you come across these? I would like to know the context to give more details. AFAIK its like this
Restore interrupt: means restore interrupt flag to the state prior ie old state void _restore_interrupts(unsigned int);
registers and interrupts in assembly

registers and interrupts in assembly


By : SJB
Date : March 29 2020, 07:55 AM
may help you . I'm reading the manual on nasm programming in Linux and there is a thing I can't find the answer to. , Here is what your program do :
code :
; print a byte to stdout
mov eax, 4           ; the system interprets 4 as "write"
mov ebx, 1           ; standard output (print to terminal)
mov ecx, buffer      ; pointer to the value being passed
mov edx, 1           ; size of the buffer
int 0x80             ; call the kernel
GameBoy compiler with system registers and interrupts

GameBoy compiler with system registers and interrupts


By : user3049603
Date : March 29 2020, 07:55 AM
hope this fix your issue The usual tactic is to create your own pointers to system registers. I don't know the address of DDRD, but something like this should to the trick:
code :
volatile unsigned char *reg_DDRD = (unsigned char *)0xE000;
*reg_DDRD = 0xAB;
#define DDRD (*reg_DDRD)
DDRD = 0xAB;
     org 38h   ; or wherever the gameboy CPU jumps to on interrupt
 jp _intr_function
void intr_function()
{
     asm(" push af");
     asm(" push bc");
     asm(" push de");
     asm(" push hl");

     // ... now do what you like here.

     asm(" pop hl");
     asm(" pop de");
     asm(" pop bc");
     asm(" pop af");
 }
Why do we need to disable interrupts when enabling A20 sometimes?

Why do we need to disable interrupts when enabling A20 sometimes?


By : Abhijit Mukherjee
Date : March 29 2020, 07:55 AM
Any of those help When you talk to the keyboard controller you definitely want to send it the whole command as an uninterrupted sequence. So you will have to stop anyone from interrupting(!) you.
The fast_a20_gate doesn't have that problem. It is not a sequence, but just one command - a single bit actually. And if someone should happen to interfere and flip the bit, you will still set it anyway in the end.
Disabling/Enabling interrupts on x86 architectures

Disabling/Enabling interrupts on x86 architectures


By : Ali
Date : March 29 2020, 07:55 AM
I wish this helpful for you Clearing [E|R]FLAGS.IE with e.g. CLI disables all (maskable) interrupts on a CPU. For a number of reasons it may be undesirable (e.g. you want to allow some or, perhaps, you don't want overheads of virtualizing CLI in a VM).
Another way of achieving the goal is to tell to the interrupt controller (either the old 8259 PIC or the Pentium APIC/IOAPIC) that you don't want to service interrupts whose priority is below a certain level. For that you need to communicate with the controller, which itself may incur additional overhead (talking to both real and virtual hardware is slow).
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