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XPath - Selecting xml nodes with attributes with names that follow pattern


XPath - Selecting xml nodes with attributes with names that follow pattern

By : Vinod
Date : November 22 2020, 02:59 PM
I wish did fix the issue. name() returns the name of the node you're currently examining, which in this case is the /Foo/Bar/Attributes node, so name() will return "Attributes".
You want to look at the attributes of /Foo/Bar/Attributes, so you probably want something more like this:
code :
/Foo/Bar/Attributes/@*[starts-with(name(), 'foo')]


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XPath (c#) Selecting nodes, then further selecting nodes based on the first query

XPath (c#) Selecting nodes, then further selecting nodes based on the first query


By : Flavio Evangelista
Date : March 29 2020, 07:55 AM
around this issue I have the following XML , Try:
code :
questions/question[questiontext='How old are you?']/options/option[text()='71+']
php xpath select nodes based on values of two attributes (edit) AND its parents attributes

php xpath select nodes based on values of two attributes (edit) AND its parents attributes


By : TeTe A-ov
Date : March 29 2020, 07:55 AM
around this issue xpath 1.0 - I had to change the approach, because the XML has changed. , Try
code :
//scale[@gender="*" or @gender="m"][@age="*" or @age="39-59"]
$str=<<<XML
<scales>
    <scale id="1" gender="*" age="*">
        <d>5</d>
        <d>9</d>
    </scale>
    <scale id="2" gender="m" age="*">
        <d>3</d>
        <d>0</d>
    </scale>
    <scale id="3" gender="*" age="19-39">
        <d>12</d>
        <d>19</d>
    </scale>
</scales>
XML;
$xml=simplexml_load_string($str);
$result=$xml->xpath('//scale[@gender="*" or @gender="m"][@age="*" or @age="39-59"]');
foreach($result as $node)
{
    echo $node->attributes()->id."\n";
}
XPath Exclude nodes based on attributes of multiple other nodes

XPath Exclude nodes based on attributes of multiple other nodes


By : Ibrahim Alazawy
Date : March 29 2020, 07:55 AM
may help you . The contains function is used to find substrings in other strings, not values in a node set. The operator you're looking for is =, which is existentially quantified in XPath - the expression a = b where a and/or b are node sets will succeed if any node in the set a matches any in b.
code :
//static/list[@id='ResponseActionList']/listRow[@rsp_cd='R2' and
    not(@act_cd = //static/list[@id='ActExcludeList']/listRow/@act_cd)]
python lxml xpath get the nodes attributes with specific string pattern

python lxml xpath get the nodes attributes with specific string pattern


By : Mujahid Ali
Date : March 29 2020, 07:55 AM
To fix this issue Now you are using tag div, not a:
'//a[contains(@href,"mailto") and @class="dev-link"]/text()'
code :
def get_app_from_link(self,link)::
    # your code
    return name, developer
XPath expression: selecting text nodes between element nodes

XPath expression: selecting text nodes between element nodes


By : vijay dubey
Date : March 29 2020, 07:55 AM
With these it helps The reason why the two text nodes aren't in the result of your XPath is because * only match elements. To match both element and text node you can use node() instead :
code :
//node()[preceding::p[contains(.,"TextB")] and following::p[contains(.,"TextD")]]
//text()[preceding::p[contains(.,"TextB")] and following::p[contains(.,"TextD")]]
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