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How would I return the result of SQL math operations?


How would I return the result of SQL math operations?

By : TA Menezes
Date : November 22 2020, 02:59 PM
I wish this helpful for you How to make really simple query complex?
One funny way(not best performance) to do it is:
code :
SELECT final.EmployeeType, SUM(salary) AS difference
FROM (
  SELECT b.EmployeeType, b.EmployeeSalary AS salary
  FROM tab b
  JOIN (SELECT EmployeeType, GROUP_CONCAT(EmployeeSalary ORDER BY Created DESC) AS c
        FROM tab
        GROUP BY EmployeeType
        HAVING COUNT(*) > 1) AS sub
    ON b.EmployeeType = sub.EmployeeType
    AND FIND_IN_SET(b.EmployeeSalary, sub.c) = 1
  UNION ALL
  SELECT b.EmployeeType, -b.EmployeeSalary AS salary
  FROM tab b
  JOIN (SELECT EmployeeType, GROUP_CONCAT(EmployeeSalary ORDER BY Created DESC) AS c
        FROM tab
        GROUP BY EmployeeType
        HAVING COUNT(*) > 1) AS sub
    ON b.EmployeeType = sub.EmployeeType
    AND FIND_IN_SET(b.EmployeeSalary, sub.c) = 2
) AS final
GROUP BY final.EmployeeType;
SELECT EmployeeType, SUM(CASE rn WHEN 1 THEN EmployeeSalary 
                                 ELSE -EmployeeSalary END) AS difference
FROM (SELECT *,
       ROW_NUMBER() OVER(PARTITION BY EmployeeType ORDER BY Created DESC) AS rn
      FROM #tab
     ) AS sub
WHERE rn IN (1,2)
GROUP BY EmployeeType
HAVING COUNT(EmployeeType) > 1
SELECT EmployeeType, SUM(CASE rn WHEN 1 THEN EmployeeSalary 
                          ELSE -EmployeeSalary END) AS difference
FROM (
       SELECT t1.EmployeeType, t1.EmployeeSalary,
        count(t2.Created) + 1 as rn
      FROM #tab t1
      LEFT JOIN #tab t2
        ON t1.EmployeeType = t2.EmployeeType
       AND t1.Created < t2.Created
      GROUP BY t1.EmployeeType, t1.EmployeeSalary
     ) AS sub
WHERE rn IN (1,2)
GROUP BY EmployeeType
HAVING COUNT(EmployeeType) > 1;


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All math operations return as an integer?

All math operations return as an integer?


By : artychaud
Date : March 29 2020, 07:55 AM
I wish this helpful for you The return an int because most maths operations need larger numbers than a short can contain. The BCL is there for use by many programmers and the creators had to balance readability, usability and performance amongst others in order to create classed that are generally useful.
As method signatures do not take return type into account, they had to decided what would be most useful as a return type (short, int, long etc) for these functions. They decided that int was best.
Why do Python's math.ceil() and math.floor() operations return floats instead of integers?

Why do Python's math.ceil() and math.floor() operations return floats instead of integers?


By : Jake O'Connor
Date : March 29 2020, 07:55 AM
seems to work fine The range of floating point numbers usually exceeds the range of integers. By returning a floating point value, the functions can return a sensible value for input values that lie outside the representable range of integers.
Consider: If floor() returned an integer, what should floor(1.0e30) return?
C++ simple math operations with floats and a wrong result?

C++ simple math operations with floats and a wrong result?


By : Nib
Date : March 29 2020, 07:55 AM
hope this fix your issue I need simple math operations with some floats like "3.3 - 2.6". The result is 0.700001. I have no idea why there are numbers like 0.700001. , Maybe that happens because of float precision. Try using double.
Using angularjs, how to perform math operations on textboxes and see result as the values are being typed in?

Using angularjs, how to perform math operations on textboxes and see result as the values are being typed in?


By : roads
Date : March 29 2020, 07:55 AM
help you fix your problem In your code, the calculation of the sum would only be executed once.
You need to add a watch of the scope or bind a function to ng-change event in order to keep the sum updated while you change the numbers.
code :
<div ng-app="adder" ng-controller="addcontrol">
    <table>
    <tr>
        <th>Value</th><th>Quantity</th>
    </tr>
    <tr ng-repeat="number in numbers">
        <td><input type="text" ng-change="update()" ng-model="number.val"></td>
        <td><input type="text" ng-change="update()" ng-model="number.qty"></td>
        <td><input type="button" ng-click="deleteNumber($index)" value= "Delete"></td>pp',[]);
    </tr>
    </table>
    <input type="button" ng-click="add()" value="Add new">Result : {{sum}}
</div>
var myapp = angular.module('adder', []);
myapp.controller('addcontrol', function($scope) {
  $scope.numbers = [{
      val: 100,
      qty: 200,
    }

  ];

  $scope.add = function() {
    $scope.numbers.push({
      val: 0,
      qty: 0
    });
  };

  $scope.deleteNumber = function(val) {
    numbers.splice(val, 1);
    $scope.update();
  };

  $scope.update = function() {
    var result = 0;
    angular.forEach($scope.numbers, function(num) {
      result += (num.val * num.qty);
    });
    $scope.sum = result;
  };
});
Wrong result of JavaScript function (math operations)

Wrong result of JavaScript function (math operations)


By : Hosting CouponsDisco
Date : March 29 2020, 07:55 AM
wish help you to fix your issue Can someone please breakdown this script for me and tell me how the outcome is 30105? alot guys ,
three(5)
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