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Passing template function and overload as function argument


Passing template function and overload as function argument

By : Atakishiyev Nicat
Date : November 22 2020, 02:59 PM
I hope this helps you . There are no partial specializations for function templates. But I think you might have a bigger misunderstanding: "Is is possible to mix template functions and overloads when passing a function pointer ..." Overload resolution happens when the function pointer is created. There is no mix anymore, once the function pointer has been created.
That said, what you appear to want is a policy. Hard to google that when you don't know the name, I know.
code :


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Template or function overload for generic argument

Template or function overload for generic argument


By : بيلسان الاخرس
Date : March 29 2020, 07:55 AM
Any of those help Overloaded functions is the best approach for your use case.
I usually go by the following rules:
Can I have a function/method passing an argument by reference and an overload passing it by value in C++?

Can I have a function/method passing an argument by reference and an overload passing it by value in C++?


By : Arwan Maulana
Date : March 29 2020, 07:55 AM
Any of those help You can accomplish something similar in C++ by providing an explicit cast to the desired type.
code :
struct Foo
{
    Foo(int /*bar*/) {}
    Foo(int &/*bar*/) {}
};


int main()
{
    int value = 5;
    Foo foo(static_cast<const int&>(value));

    return 0;
}
Argument deduction with template member function and non-template overload

Argument deduction with template member function and non-template overload


By : Noam Velleman
Date : March 29 2020, 07:55 AM
With these it helps If you specify in the declaration of add_to_header that it needs to be able to call to_string on its arguments then the template overload will be eliminated through SFINAE:
code :
void add_to_header( const std::string &key, const std::string &val );

template<typename T> auto add_to_header( const std::string &key, const T &val )
-> decltype(std::to_string(val), void())  // uses comma operator
{
    add_to_header( key, std::to_string( val ) );
}
template<typename T> constexpr bool ToStringable() {
    using namespace std;
    void to_string(...);
    return is_same<string, decltype(to_string(declval<T>()))>::value;
}

template<ToStringable T>
void add_to_header( const std::string &key, const T &val )
{
    add_to_header( key, std::to_string( val ) );
}
Overload function template based on parameter function argument type

Overload function template based on parameter function argument type


By : Max Angel
Date : March 29 2020, 07:55 AM
wish helps you
My question is, when Fn is a getter wouldn't the former std::result_of fail, effectively disabling one of the overloaded maps?
code :
struct Foo {
    Foo(int i) : i(i) { }
    int bar() const { return i; }
    int i;
};
using T = std::result_of_t<decltype(&Foo::bar)(Foo )>;
static_assert(std::is_same<T, int>{}, "!");
template <class A, class F, class B = std::result_of_t<F(A)>>
std::vector<B> map(std::vector<A> xs, F f)
{
    auto binder = std::bind(f, std::placeholders::_1);

    std::vector<B> r;
    for (auto& x : xs) {
        r.push_back(binder(x));
    }
    return r;
}
std::vector<int> vs{1, 2, 3, 4, 5};
std::vector<double> ds = map(vs, [](int i){return i * 2.0; });
std::vector<Foo> foos{1, 2, 3, 4, 5};
std::vector<int> is = map(foos, &Foo::bar);
What's the correct syntax for passing an explicitly specified function template overload as a template parameter?

What's the correct syntax for passing an explicitly specified function template overload as a template parameter?


By : Buddy Cobb
Date : March 29 2020, 07:55 AM
I wish this help you Consider the following two function templates , Ok, I figured it out myself:
code :
h<void(std::vector<int>&)>(g, vec);
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