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Perl: Array of Array References


Perl: Array of Array References

By : Edward Shiers
Date : November 22 2020, 02:59 PM
may help you . As others have mentioned, you're getting confused as to when you should use the $ and @ symbols. (To be fair, it's not always obvious in Perl.) The Perl reference tutorial link glenn gave is the best resource. Maybe some examples will help:
code :
use strict;
use warnings;

my @important_years = (1066, 1492, 1776);
my @recent_years    = (2010, 2012, 2014);

my $important_years_ref = \@important_years;
my $recent_years_ref    = \@recent_years;

my @redArray = ($important_years_ref, $recent_years_ref);

printf("%s\n", $redArray[0][0]);    # 1066
printf("%s\n", $redArray[0][1]);    # 1492
printf("%s\n", $redArray[0][2]);    # 1776

printf("%s\n", $redArray[1][0]);    # 2010
printf("%s\n", $redArray[1][1]);    # 2012
printf("%s\n", $redArray[1][2]);    # 2014

# Get a reference to the "important years" array
my $important_years_copy_ref = $redArray[0];
printf("%s\n", $important_years_copy_ref->[2]);  # 1776

# Or make brand new array by dereferencing
# the "important years" reference stored in @redArray
my @important_years_copy = @{$redArray[0]};
printf("%s\n", $important_years_copy[2]);        # 1776


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Match Array to a Value within an Array of References - Perl

Match Array to a Value within an Array of References - Perl


By : Ronit B
Date : March 29 2020, 07:55 AM
will help you This should put you on the right track. Two problems I see with your code - an array of arrays should have normal parentheses on the outer part, and use the ~~ operator to compare arrays for equality.
code :
my @holidays = ([2012,'01','02'],[2012,'01','16'],[2012,'02','20'],[2012,'04','16'],  
[2012,'05','28'],[2012,'07','04'],[2012,'09','03'],[2012,'10','08'],[2012,'11','12'], 
[2012,'11','22'],[2012,'12','25']);
my $i;
my @duedate = [2012, '01', '02'];

for ($i = 0; $i < @holidays; $i++)
{
    if (@holidays[$i] ~~ @duedate)
    {
        print "matched!!";
    }
}
How to access an element in a Perl array from a reference to an array of references

How to access an element in a Perl array from a reference to an array of references


By : 许智敏
Date : March 29 2020, 07:55 AM
this will help The syntax error is coming from $$#TransRef which should be $#$TransRef. By misplacing the # you accidentally commented out the rest of the line leaving:
code :
for ($Loop = 0; $Loop <= $$
{
   $TransArrRef = $$TransRef[$Loop];
   ...
}
for my $loop (0 .. $#$TransRef) {
    $TransID = $TransRef->[$loop]->[0];
    #   ...
}
Sorting an array of array references in Perl

Sorting an array of array references in Perl


By : 高英杰
Date : March 29 2020, 07:55 AM
will help you You're passing an array reference into the subroutine and then trying to use it as an array. You need to dereference it first.
code :
sub sort_arr {
    my ($arr) = @_;
    my @sorted_arr = sort { $a->[1] cmp $b->[1] } @{ $arr };
    return \@sorted_arr;
}
How do I serialize an array of array-references in Perl?

How do I serialize an array of array-references in Perl?


By : Wayne McKinney
Date : March 29 2020, 07:55 AM
should help you out I vote for JSON (or Data::Serializer as mentioned in another answer, in conjunction with JSON).
The JSON module is plenty fast and efficient (if you install JSON::XS from cpan, it will compile the C version for you, and use JSON will automatically use that).
How to union two array references containing array references in perl?

How to union two array references containing array references in perl?


By : Monty Khurana
Date : March 29 2020, 07:55 AM
wish helps you Let's say I have an array reference which looks like - , Use a hash of hashes to represent the existing elements of the union:
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