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Specman: How to find if a list of bytes exists in another list taking order of the list into account


Specman: How to find if a list of bytes exists in another list taking order of the list into account

By : Essam Haroon
Date : November 23 2020, 09:01 AM
I wish this help you I have a payload which is a lists of type bytes: , The following code should work:
code :
if (item.size()==0) {return TRUE};
for i from 0 to payload.size()-item.size() {
    if (item == payload[i..i+item.size()-1]) {
        return TRUE;
    };
};
return FALSE;


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Specman e: How to constrain distribution of values inside list of list?

Specman e: How to constrain distribution of values inside list of list?


By : user2786837
Date : March 29 2020, 07:55 AM
it fixes the issue You have soft in there twice, though that isn't the problem. You forgot to put a == before select. I'd write it like this:
code :
  keep for each (elem) in my_list {
    soft elem.comparator[0] == select {
      30: [-1000 .. -50]; -- Big negative values
      40: [-49 ..49]; -- Medium values
      30: [50..1000]; -- Big positive values           
    };
    // Same for elem.comparator[1]
  };
use Streams to generate a new list taking into account all the first list elements

use Streams to generate a new list taking into account all the first list elements


By : Avinash kumar
Date : March 29 2020, 07:55 AM
With these it helps I would like to map a list to another one. The decision is to be made on all the elements of the first list. Here is how it would look like, in crappy code : , For example:
code :
class MatchingClass {
    public List<TheEnums> getMatchingEnums(List<String> givenParameters) {

        List<TheEnums> enumsList = Arrays.asList(TheEnums.values());

        return enumsList.stream()
                .filter(e -> givenParameters.containsAll(Arrays.asList(e.getParams())))
                .collect(Collectors.toList());
    }
}
How to combine elements from the list taking into account index of the list?

How to combine elements from the list taking into account index of the list?


By : Bharath Maripelly
Date : March 29 2020, 07:55 AM
wish of those help Ok. You can iterate through the array starting from index 1. Then inside the first loop have a second loop. There you concatenate the strings from the lists and if list has only one element then just concatenate it.
code :
    List<String>[] tab = new ArrayList[5];
    tab[0] =  new ArrayList<String>(Arrays.asList("1242"));
    tab[1] =  new ArrayList<String>(Arrays.asList("London", "Paris"));
    tab[2] =  new ArrayList<String>(Arrays.asList("England", "France"));
    tab[3] =  new ArrayList<String>(Arrays.asList("Finance"));
    tab[4] =  new ArrayList<String>(Arrays.asList("No"));

    StringBuffer buffer;

    for(int j=1; j<=2; j++){
        buffer = new StringBuffer(tab[0].get(0)).append(" ");
        for(int i = 1; i < tab.length; i++){

          List<String> list = tab[i];

          if(list.size() == 1){
             buffer.append(list.get(0)).append(" ");
          }else{
             buffer.append(list.get(j - 1)).append(" ");
          }



        }
        System.out.println(buffer.toString());
    }
How to find an item in a list that exists as a sub-string in all the items of a list python

How to find an item in a list that exists as a sub-string in all the items of a list python


By : Nick Jones
Date : March 29 2020, 07:55 AM
hope this fix your issue Break down the problem into pieces.
Start off by making a function that checks if one string is in a sequence of strings:
code :
def check_one(string, seqs):
    for seq in seqs:
        if string not in seq:
            return False
    return True
def check_all(strings, seq):
    result = []

    for string in strings:
        if check_one(string, seq):
            result.append(string)

    return result
short_str_list = ["aga", "ttt", "aca"]
seq_list = ["atcgcgtacat", "acatcgggattt", "tttacagtgtgtggg"]

print(check_all(short_str_list, seq_list))
# ['aca']
print([x for x in short_str_list if all(x in y for y in seq_list)])
# ['aca']

print(list(filter(lambda x: all(x in y for y in seq_list), short_str_list)))
# ['aca']
How to search in a list whether a list of given items exists in the same order

How to search in a list whether a list of given items exists in the same order


By : Vinicius de Sá
Date : March 29 2020, 07:55 AM
To fix the issue you can do I need to check if a list contains all the items and in the same sequence using LINQ and if match found return the last matching element. , You could do it with Linq.
code :
var allWords = new List<string> { "A", "B", "C", "D", "E", "F","D", "E", "E"};
var words = new List<string>() {"D","E"  };
var indexOfLastOccuranceOfSequence = Enumerable.Range(0, allWords.Count - words.Count + 1)
        .Select(a => allWords.Skip(a).Take(words.Count)).ToList()
        .FindLastIndex(a => a.SequenceEqual(words));
var indexOfLastElement = indexOfLastOccuranceOfSequence+ words.Count() - 1;
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