 Store date as unix timestamp or TIMESTAMP data type in MySQL?
By : user3542137
Date : March 29 2020, 07:55 AM
wish help you to fix your issue Usually it does not matter whether you use TIMESTAMP or DATETIME datatype.
In older versions, TIMESTAMP was 4 bytes and DATETIME was 8. Think of DATETIME as a picture of a clock; think of TIMESTAMP as an instant in time, worldwide. That is, if you connect to the same database, but from a different timezone, a DATETIME will look the the same, but a TIMESTAMP will be adjusted for timezone. NOW(), SELECTing into PHP, etc, are compatible with both. Both are externally seen as a string, such as '2015-04-25 17:09:01'. Since TIMESTAMP is stored as a 32-bit integer (but you don't see that), it is limited to ~1970-2038. Since DATETIME is clock time, there will be a missing/extra hour twice a year if you switch to/from daylight savings time.
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 How to let Timestamp object show in type long in JSON?
By : Tommi Jacky Jones
Date : March 29 2020, 07:55 AM
it should still fix some issue Use .getTime() to convert in to long. If you are getting an object in variable "created" then convert it into long :
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 What format should I use to store timestamp in JSON for mongodb queries used in nodejs?
By : François Chevallier
Date : March 29 2020, 07:55 AM
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 JS - JSON: adding a keypair in each object by calculating the difference in time now and a timestamp in the JSON object
By : Matt Ferancini
Date : March 29 2020, 07:55 AM
this will help I know you're aware of the forEach method, but with that, you're making changes to the original array, if you'd like make a new copy of the array, you can use map. Then of course to make 'clones' of the objects within the array by making use of destructuring. Edit code :
const array = [{"id": 1,"timestamp": 1545311087282}, {"id": 2, "timestamp": 1545311148254}];
const now = new Date().getTime();
// New copy.
const newArray = array.map(o => ({...o, diff: now - o.timestamp}));
console.log(array);
console.log(newArray);
// Changes original.
array.forEach(o => o.diff = now - o.timestamp);
console.log(array);
const array = [{"id": 1,"timestamp": 1545311087282}, {"id": 2, "timestamp": 1545311148254}];
const now = new Date().getTime();
// Difference in minutes.
const diff = time => new Date(now).getMinutes() - new Date(time).getMinutes();
// New copy.
const newArray = array.map(o => ({...o, minsDiff: diff(o.timestamp)}));
console.log(array);
console.log(newArray);
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 Get json object that has latest timestamp using jq
By : user2914805
Date : March 29 2020, 07:55 AM
I hope this helps you . Simply sort by .createdDate and (assuming you only want one value even if there is more than one with the greatest .createdDate value), select the last one: code :
.items
| sort_by(.createdDate)[-1].description
.items
| sort_by(.createdDate)
| (.[-1].createdDate) as $max
| .[]
| select($max == .createdDate)
| .description
|
code :
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