Spark: join key-tuple pairs into key-list value

Spark: join key-tuple pairs into key-list value

By : Superduck
Date : November 26 2020, 09:01 AM
it fixes the issue You could do a multi-join or you could save yourself from nested syntax and apply a version of cogroup instead. However, since cogroup() only allows you to group up to 4 RDD's you can kind of monkey patch it to group more. Below is an example of a multiCogroup() function:
code :
def multiCogroup[K : ClassTag, V : ClassTag](numPartitions: Int, inputRDDs: RDD[(K, V)]*) : RDD[(K, Seq[V])] = {
  val cg = new CoGroupedRDD[K](inputRDDs.toSeq, new HashPartitioner(numPartitions))
  cg.mapValues { case iterables => iterables.foldLeft(Seq[V]())(_ ++ _.asInstanceOf[Iterable[V]].toSeq) }
import org.apache.spark.rdd._
import org.apache.spark.HashPartitioner
import scala.reflect.ClassTag

val rdd1 = sc.parallelize(Seq(("a", 1),("b", 2),("c", 3),("d", 4)))
val rdd2 = sc.parallelize(Seq(("a", 4),("b", 3),("c", 2),("d", 1)))
val rdd3 = sc.parallelize(Seq(("c", 0),("d", 0),("e", 0)))
val rdd4 = sc.parallelize(Seq(("a", 5),("b", 5),("e", 5)))
val rdd5 = sc.parallelize(Seq(("b", -1),("c", -1),("d", -1)))

val combined = multiCogroup[String, Int](2, rdd1, rdd2, rdd3, rdd4, rdd5)

// (d,List(4, 1, 0, -1))
// (b,List(2, 3, 5, -1))
// (e,List(0, 5))
// (a,List(1, 4, 5))
// (c,List(3, 2, 0, -1))

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Spark find key/value pairs with key equals to other values and join

Spark find key/value pairs with key equals to other values and join

By : Drew
Date : March 29 2020, 07:55 AM
seems to work fine Using purely Scala collection functions (in Set) - I don't use Spark:
code :
val ex = Set("T" -> "V", "V" -> "W", "A" -> "B", "B" -> "C")

val keysEquallingValues = ex.flatMap { tuple => 
  ex.find(t => tuple._2 == t._1).map(t => tuple -> t)
val r = ex ++ keysEquallingValues.map(pair => pair._1._1 -> pair._2._2)
How to convert list pairs into tuple pairs

How to convert list pairs into tuple pairs

By : Marco Constâncio
Date : March 29 2020, 07:55 AM
hope this fix your issue How do you turn a list that contain pairs into a list that contains tuple pairs by using easy programming e.g for loop? x,y = ...?
code :
def read_numbers():
    numbers = ['68,125', '113,69', '65,86', '108,149', '152,53', '78,90']
    return [tuple(map(int,pair.split(','))) for pair in numbers]
Comparing a tuple of a pair to a list of tuple pairs

Comparing a tuple of a pair to a list of tuple pairs

By : lydia oye
Date : March 29 2020, 07:55 AM
it should still fix some issue Assuming the following function calculate the distance within 2 points:
code :
def distance(point_a, point_b):
    """Returns the distance between two points."""
    x0, y0 = point_a
    x1, y1 = point_b
    return math.fabs(x0 - x1) + math.fabs(y0 - y1)
def nearest(point, all_points):
    closest_point, best_distance = None, float("inf")
    for other_point in all_points:
        d = distance(point, other_point)
        if d < best_distance:
             closest_point, best_distance = other_point, d
    return closest_point
def nearest(point, all_points):
    """Returns the closest point in all_points from the first parameter."""
    distance_from_point = functools.partial(distance, point)
    return min(all_points, key=distance_from_point)
Pick from list of tuple combination pairs such that each tuple element appears at least twice

Pick from list of tuple combination pairs such that each tuple element appears at least twice

By : ScrambledEgg
Date : March 29 2020, 07:55 AM
I wish did fix the issue. The easiest way to get each name exactly twice is the following, I guess:
code :
lst = ["John", "Mike", "Mary", "Jane"]  # not shadowing 'list'

pairs = list(zip(lst, lst[1:]+lst[:1]))
# [('John', 'Mike'), ('Mike', 'Mary'), ('Mary', 'Jane'), ('Jane', 'John')]
Filter a list of pairs (tuples) where the tuple doesn't include any value from another list

Filter a list of pairs (tuples) where the tuple doesn't include any value from another list

By : Nguyễn Thanh Hoàng
Date : March 29 2020, 07:55 AM
With these it helps I have a list of tuples: , Flat is better than nested
code :
blacklist = {p[0] for p in blacklist_of_tuples}
[p for p in my_list if p[0] not in blacklist and p[1] not in blacklist]
[p for p in my_list if not any(el in blacklist for el in p)]
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