 XSLT root tag namespace instead of element attribute namespace
By : Edwin Morales
Date : March 29 2020, 07:55 AM
this one helps. You need to insert the namespace node onto the document element of your result tree. There are several ways to do this, depending on whether you're using XSLT 1.0 or 2.0. The following is a 2.0 solution. I'm assuming that you're doing a modified identity transform on the input document (your question didn't really specify): code :
<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<!-- special rule for the document element -->
<xsl:template match="/*">
<xsl:copy>
<!-- Add a namespace node -->
<xsl:namespace name="mynamespace" select="'somenamespace'"/>
<xsl:apply-templates select="@* | node()"/>
</xsl:copy>
</xsl:template>
<!-- the identity template -->
<xsl:template match="@* | node()">
<xsl:copy>
<xsl:apply-templates select="@* | node()"/>
</xsl:copy>
</xsl:template>
<!-- the rest of your rules -->
</xsl:stylesheet>
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 XSLT to copy element without namespace
By : user7369918
Date : March 29 2020, 07:55 AM
will help you The xmlns="" is required because you're asserting a default namespace (with xmlns="http://www.bazaarvoice.com/xs/PRR/ProductFeed/5.6") and then outputting nodes which are not in that namespace. For XML to represent that properly, it has to cancel the default namespace.
You haven't told us how validation is failing. If it's failing because those nodes should be in the specified namespace, they need to either be in that namespace before you copy them, or you need to replace the xsl:copy-of operation with one that explicitly reconstructs them by extracting their localname and using that and the desired namespace as parameters of an xsl:element operation. The items listed at right under Related will tell you more about this.
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How to add attributes with namespace with XSLT when there is a default namespace on the XML
By : Fran Blythe
Date : March 29 2020, 07:55 AM
I hope this helps . I also need to keep the default namespace (which can change from document to document code :
<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:deltaxml="http://www.deltaxml.com/ns/well-formed-delta-v1">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:strip-space elements="*"/>
<!-- identity transform -->
<xsl:template match="@*|node()">
<xsl:copy>
<xsl:apply-templates select="@*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="*:section[@id]">
<xsl:copy>
<xsl:attribute name="deltaxml:key" select="@id"/>
<xsl:apply-templates select="@*, node()"/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
<section xmlns="http://quark.com/smartcontent/2.0"
id="_63f6a0c9-bac8-4a15-854c-03d80bd46b64"
type="clientFactsheet">
<!-- content -->
</section>
<?xml version="1.0" encoding="UTF-8"?>
<section xmlns="http://quark.com/smartcontent/2.0"
xmlns:deltaxml="http://www.deltaxml.com/ns/well-formed-delta-v1"
deltaxml:key="_63f6a0c9-bac8-4a15-854c-03d80bd46b64"
id="_63f6a0c9-bac8-4a15-854c-03d80bd46b64"
type="clientFactsheet"><!-- content --></section>
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 How to copy parent node namespace to child element using xslt?
By : user3221978
Date : March 29 2020, 07:55 AM
I hope this helps . Here is the solution (by Transforming the XML Data using Java's XSLT APIs), As you may also have noticed.. JAXB alone cannot meet this requirement, but after marshalling the object to a formatted XML String (as u have shown) you can then post process/transform it accordingly using a suitable XSLT file code :
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:strip-space elements="TrackAndTrace"/>
<xsl:strip-space elements="Request"/>
<xsl:template match="@*|node()">
<xsl:copy>
<xsl:apply-templates select="@*|node()"/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
<xsl:stylesheet version="1.0" xmlns:xsl="w3.org/1999/XSL/Transform" xmlns:ns4="dummy.com/xsd/naku_001">
<xsl:strip-space elements="ns4:TrackAndTrace"/>
<xsl:strip-space elements="ns4:Request"/>
<xsl:template match="@*|node()">
<xsl:copy>
<xsl:apply-templates select="@*|node()"/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
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XSLT namespace and default namespace issue
By : user5082540
Date : March 29 2020, 07:55 AM
should help you out Do you really need all that code? Or are you just using this as an incantation, in the hope it will somehow appease the evil spirits? Like what does xpath-default-namespace do in an XSLT 1.0 stylesheet? (Answer: either nothing, or produce a fatal error - depending on how tolerant your processor is).
Now, if your XML example is representative, then all you need to do is:
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code :
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