 C++, pass a function of n arguments as an argument
By : kunal veera
Date : March 29 2020, 07:55 AM
around this issue C++ is a statically typed language. Every object in C++, whether a function pointer, or whatever, must have a specific type. And the type of a function pointer is based on the types of arguments that the function to be pointed to is given.
A template is not an object, so you can't get a pointer to one. You can get a pointer to an instantiation of a template. Using your func definition, func is a function that takes a const int* and a short. You can get a pointer to func. But func is a template; you can't get a pointer to a template.
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 How to pass non default argument with default arguments in python django forms
By : Wybren Oppedijk
Date : March 29 2020, 07:55 AM
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 Pass argument as default argument to all unnamed function arguments
By : Jakky187
Date : March 29 2020, 07:55 AM
To fix the issue you can do Use formals() to return a list of arguments, length() to get the number of arguments, and replicate to create a list of 'default' arguments the right length (minus the arguments set manually). code :
do.call("list.dirs", c(list("."), replicate(length(formals("list.dirs"))-1,expr = "FALSE")))
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 python 2.7, functions with positional, keyword arguments as well as variable number of arguments (arbitrary argument lis
By : Nathan Fagundo
Date : March 29 2020, 07:55 AM
I hope this helps . This is a Python 3 feature, introduced in PEP 3102. ( Python, default keyword arguments after variable length positional arguments) In Python 2, you will have to extract the keyword arguments from **kwargs: code :
def foo(positional arguments, *args, **kwargs):
# for a required positional argument
try:
kwarg = kwargs.pop('kwarg')
except KeyError as e:
raise TypeError('Required positional argument not found', e)
# or for an optional positional argument
kwarg = kwargs.pop('kwarg', None)
if kwargs:
raise TypeError('Unexpected positional arguments', kwargs)
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Is it OK to pass pandas GroupBy functions as argument in python function? and how should I pass their arguments?
By : Ben Makuh
Date : March 29 2020, 07:55 AM
Hope this helps It is ok to pass anything you want, if it works and serves you well. You can pass function's agrs either as an additional dict/tuple argument, or just use *args and **kwargs. still, it is unclear what you want to achieve here. First, It looks like you're messing with data and df in your function. Second, if I understand correctlly, pd.core.groupby.GroupBy is a class of a data-object - it is what you'll get from df.groupby, not the other way around. thus, you shouldn't use it here. code :
def foo(df, agg='mean'):
momentum = df.groupby('grouper').agg(agg)
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code :
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