Check if pattern exists in a String

» java » Check if pattern exists in a String

By : nick04

Date : November 28 2020, 09:01 AM

will be helpful for those in need I would like to check if a pattern exists in a String using iteration. , Why not this:

code :

public static void main(String args[]) {
    String pattern = "abc";
    String letters = "abcdef";

    char[] patternArray = pattern.toCharArray();
    char[] lettersArray = letters.toCharArray();
    boolean matched = false;
    for(int i = 0; i< lettersArray.length-patternArray.length && !matched; i++){
        for(int j = 0; j < patternArray.length;j++){
            if(patternArray[j] == lettersArray[i+j]&&j+1==patternArray.length){
                matched = true;
                System.out.println("true");
            }
            else if(i+1 == lettersArray.length-patternArray.length && j+1 == patternArray.length){
                System.out.println("false");
        }
    }
}

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XSLT - Check if pattern exists in an element string

By : Yevhenii Kozlovsky

Date : March 29 2020, 07:55 AM

Any of those help I have the following element as part of a larger XML , I think all you need is:

code :

matches(@V,'\[[A-Z][A-Z]\]')

Check if string exists in meta key string using meta_query check in wordpress get_posts function

By : Akshay Kumar

Date : March 29 2020, 07:55 AM

seems to work fine I believe this may be happening because you are storing multiple email addresses in one key, as opposed to having multiple keys with one email address each.
Because of this, IN will not work as it checks if a given value exists within a set of possibilities (similar to how the PHP in_array() works).

code :

bob.dougal@gmail.com, 1bob.dougal@company.com, bob.dougal@hotmail.com
bob.dougal@gmail.com, 12bob.dougal@company.com, bob.dougal@hotmail.com
bob.dougal@gmail.com, 123bob.dougal@company.com, bob.dougal@hotmail.com

Check if a string exists in another string having a specific pattern in Javascript

By : usosystem

Date : March 29 2020, 07:55 AM

seems to work fine I solved the problem by using one more condition in the if statement like this

code :

if (b.Channel.includes('SIP') && b.Channel.includes(a.name))

var obj2 = [{
  "name": "4134",
  "calls": [

  ]
}]

    var obj3 = [{ Channel: 'SIP/4134-0004462a',
        Accountcode: '7013658596'},
      { Channel: 'DAHDI-il-4134-sa',
        Accountcode: '07717754702',
      }]

var func = (obj2, obj3) => {
    obj2.forEach((a) =>
      obj3.forEach((b) => {
        if (b.Channel.includes('SIP') && b.Channel.includes(a.name)) a.calls = (a.calls || []).concat(Object.assign({}, { MobileNo: b.Accountcode}));

      })
    );
};

func(obj2, obj3);
console.log(JSON.stringify(obj2));

[
  {
    "name": "4134",
    "calls": [
      {
        "MobileNo": "7013658596"
      }
    ]
  }
]

How to check if an item exists in a string List and if it exists, get its index

By : Amid Hafi

Date : March 29 2020, 07:55 AM

this will help Use IndexOf method to find index of item in list. This method returns -1 in case item does not exist in the list.

code :

var itemIndex = myList.IndexOf("string_to_search")

To check if a pattern exists in a String

By : user3732184

Date : March 29 2020, 07:55 AM

I wish this helpful for you The point you are missing is that Java matches() puts a ^ at the start and a $ at the end of the Regex for you. So your expression actually is seen as:

code :

^[^\w]test[ ]*[(]$

(?:.*)(?<=\s)(test(?:\s+)?\()(?:.*)

^                 Start of line - added by matches()
(?:.*)            Non-capturing group - match anything before the word, but dont capture into a group
(?<=\s)           Positive lookbehind - match if word preceded by space, but dont match the space
(                 Capturing group $1
  test(?:\s+)?    Match word test and any following spaces, if they exist
  \(              Match opening bracket
)                 
(?:.*)            Non-capturing group - match rest of string, but dont capture in group
$                 End of line - added by matches()

public class Main {
    public static void main(String[] args) {
        String s = "This is a test() function";
        String s2 = "This is a test    () function";
        System.out.println(s.matches("(?:.*)((?<=\\s))(test(?:\\s+)?\\()(?:.*)")); 
        //true
    }
}