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Creating an image element (modifying the DOM)


Creating an image element (modifying the DOM)

By : Emil
Date : November 28 2020, 09:01 AM
With these it helps I am currently taking a course on programming and am struggling with one particular question. I believe I know the answer but I would like to actually understand the concept fully.
code :
   $(document).ready(function(){
// ^ "$" = call to the linked jQuery.js file (This is the same as telling the 
//browser you want to use "ready" function from the jQuery you linked in your html)

$(document).ready(function(){
  // ^ "(document)" the document(DOM)

$(document).ready(function(){
          // ^ when the entire DOM is considered "ready" as all 
          // of the browser requests for resources are satisfied or
          // have received an error.

$(document).ready(function(){
                  // ^ If jQuery is loaded, and the entire DOM and resources have 
                  // been resolved, pass the following "function" (your jQuery code)
                  // back into the document for the browser to show/use. 
                  // (execute the code within once the page is ready.  This is 
                  // where your jQuery typically gets written/executed until you 
                  // separate it out and link your larger javascript file where your 
                  // jQuery functionality will reside and be linked to your html 
                  // document.
$('<img>', {   // Makes an image tag object. give the following attributes

src: 'images/little-book.png',  
// Defines the source of the image using current directory 
// i.e ("www.websiteAddress.com/IMAGES/LITTLE-BOOK.PNG)

alt: 'New Book',  
// Generates the image html element's "alt" value. 
// The plain text that displays if the image doesn't load.

title: 'This is a good book to read'  
// Gives the image tag a title of "This is a good book to read"

});
// Ends the image object. At this point it's been instantiated (exists) 
// and it is a well defined image object to create the html image tag from
});
var imgToInsert =   $('<img>', {
src: 'images/little-book.png',
alt: 'New Book',
title: 'This is a good book to read'
});


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Creating a slider with dots representing each image, each not returning image element?

Creating a slider with dots representing each image, each not returning image element?


By : Marian
Date : March 29 2020, 07:55 AM
like below fixes the issue Javascript:
code :
item.hasClass('active')
$(item).hasClass('active')
Pandas script modifying numbers to long float numbers when it shouldn't even be modifying that column/element

Pandas script modifying numbers to long float numbers when it shouldn't even be modifying that column/element


By : Bear
Date : March 29 2020, 07:55 AM
hop of those help? I've got a pandas script below causing me a headache because it keeps modifying my data when it shouldn't be, the example below can re-create the issue 100% perfectly. (Took me forever to find out what was causing this problem) , Try this :)
code :
csvdata = pandas.read_csv('testing.csv', dtype={'TITLE5' : 'object', 'TITLE5.1' : 'object', 'TITLE5.2' : 'object', 'TITLE5.3' : 'object'})
How can I overlay an image on an element without creating an image element?

How can I overlay an image on an element without creating an image element?


By : luojr
Date : March 29 2020, 07:55 AM
wish helps you This should be pretty close to what you are looking for. Might need to tweak background color.
CSS:
code :
.outer {
  position: relative;
}

.outer.loading:before {
  background: #fefefe url('https://www.wpfaster.org/wp-content/uploads/2013/06/loading-gif.gif') center no-repeat;
  background-size: contain;
  content: "";
  display: inline-block;
  position: absolute;
  width: 100%;
  height: 100%;
  z-index: 9999;
}
How do I replace an array element without modifying the original array and creating copy?

How do I replace an array element without modifying the original array and creating copy?


By : Tatiana Kochedykova
Date : March 29 2020, 07:55 AM
it should still fix some issue I'm trying to create a pure function that receives an array as parameter and now I want to replace an element at a given index without modifying the provided array argument. , Simply copy the array. A simple way to do that is slice:
code :
export const muFunc = (arr) => {
    var newArray = arr.slice();
    newArray[1] = 'myNewValue';
    return newArray;
};
Creating multiples of the same DOM Element Image

Creating multiples of the same DOM Element Image


By : user2167614
Date : March 29 2020, 07:55 AM
around this issue Whenever you use Javascript's appendChild or jQuery's append, when you pass it an element, that element gets removed from its previous location in the DOM (if it's in the DOM), and then gets inserted at the new position. It sounds like what you need to do is explicitly create a new element each time, which you might do with cloneNode().
Also, probably best to name your variables precisely - if turn is an image, name it to make it clear that it's an image, perhaps currentPlayerImage.
code :
const play = (event) => {
  if (gameOver === false) {
    if (event.target.innerHTML === '') {
      $(event.target).append(currentPlayerImage.cloneNode());
    }
  }
}
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