PHP undefined index id error

By : faCue

Date : November 29 2020, 09:01 AM

help you fix your problem You are sending you're POST to configuration.php not to your executer?

code :

<form class="form-horizontal" method="post" action="configuration.php" data-validate="parsley">

$requestID = $_GET['id'];

$requestID = (isset($_GET['id'])) ? $_GET['id'] : 'add ID for POST';

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Why do I keep getting an undefined index error even though var_dump() shows the index is defined?

By : Mikhail Karelov

Date : March 29 2020, 07:55 AM

This might help you Omar's answer is correct. For more detail, look at the documentation of fetchAll: PHP docs for fetchAll
The skinny is that fetchAll returns an indexed array of all rows from your query, and each if those indexed arrays contains an associative array of keys and values. As a result, the data you want is stored in $studentFunds[0]['studentFunds']

code :

$oldAmount = 0;
if( is_array( $studentFunds ) && count( $studentFunds ) == 1 )
{
   $oldAmount = $studentFunds[0]['studentFunds'];
}

Fixing Index.php line 6 error Undefined index:logout

By : Reshma Shetty

Date : March 29 2020, 07:55 AM

this will help Undefined index: logout in F:\xampp\htdocs\xxx\index.php on line 6 This is the index. , i suggestion to you, first create a function ex:

code :

<?php
function get_request($name, $default = ''){
    if(isset($_REQUEST[$name])){
        if($_REQUEST[$name] != ''){
            return $_REQUEST[$name];
        }else{
            return $default
        }
    }else{
        return $default
    }
}
?>

<?php
session_start();
date_default_timezone_set('Europe/Paris'); 

// LOGOUT
if(get_request('logout', 0) == 1)

// LOGOUT
if(isset($_GET['logout']) && $_GET['logout'] == 1)

my program A PHP Error was encountered. Message: Undefined index: jenis_kelamin and Undefined index: tanggal_lahir Filen

By : David Maria

Date : March 29 2020, 07:55 AM

I wish this helpful for you Always make use of the isset construct (whether a value is assigned to your variable or not) to check for the variables before assigning data.

code :

if(isset($_POST['jenis_kelamin']))
{
$_POST['jenis_kelamin']= strtoupper($data['siswa']['jenis_kelamin']);
}

$siswa=array('id'=>$id,'nama'=>$this->input->post('nama'),
                        'alamat'=>$this->input->post('alamat'),
                        'jenis_kelamin'=>$this->input->post('jenis_kelamin'),
                        'tanggal_lahir'=>date('Y-m-d', strtotime($this->input->post('tanggal_lahir'))));

Undefined index error - Defined index after the variable is called

By : Maicol Alencar

Date : March 29 2020, 07:55 AM

I hope this helps you . Firstly, you have no valid enctype in your form to handle files, so add it; it's required.

code :

<form action='inc/download_attachment.php' method='post' enctype='multipart/form-data'>

if (

    !empty($_FILES['attachment']) 
    && $_FILES['attachment']['size'] == 0 


) {

// do something

}

<?php 
error_reporting(E_ALL);
ini_set('display_errors', 1);

// Then the rest of your code

Fatal Error: PDO Statement Undefined Method & Undefined index?

By : Aparna

Date : March 29 2020, 07:55 AM

I wish this helpful for you You are mixing PDO with mysql and there are multiple syntax errors. Your code should be like this:

code :

<?php
error_reporting(E_ALL);
$submit = $_POST['submit'];
if($submit) {
   $name = $_POST['somename'];
   $username = $_POST['username'];
   $con = new PDO('mysql:host='.$db_hostname.';dbname='.$db_database.';charset=utf8mb4', $db_termname,$db_password, array(PDO::ATTR_EMULATE_PREPARES => false,PDO::ATTR_ERRMODE => PDO::ERRMODE_EXCEPTION));
   $stmt = $con->prepare('SELECT * FROM users WHERE username=:username');
   $stmt->bindParam(":username", $username);
   $stmt->execute();
   $row = $stmt->fetch(PDO::FETCH_ASSOC);
   if($name=='ip') {                       
      echo $row['ip'];  
   }elseif
      ($name=='uid') {
         echo $row['uid];
      }
}
?>

<form action="" method="POST">
  <input type="radio" name="somename" value="ip">IP<br>
  <input type="radio" name="somename" value="uid">UID<br>
  Enter Name: <input type="text" name="username">
  <br>
  <input type="submit" name="submit">
</form>

if($name=='ip') {  
   if($row['ip'] == 'ip') {
      echo 'Result!';
   }else{ 
      echo 'No Result!';
   }
}

if($name=='uid') {  
   if($row['uid'] == 'uid') {
      echo 'Result!';
   }else{ 
      echo 'No Result!';
   }
}