Jquery : find length of mixed list

» javascript » Jquery : find length of mixed list

By : bluforce

Date : November 29 2020, 09:01 AM

seems to work fine This is example list : , The key is to add ol to the selector of the check.

code :

var n = 0

$('ul, ol').each(function(i){ 
    if (($(this).parents('ul, ol').length + 1) > n) { n = $(this).parents('ul, ol').length + 1; }
});

$('#result').html(n);

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<ul>
    <li>Item:
        <ol>
            <li>Point:
                <div>
                    <ul>
                        <li>
                          elem1
                          <ol>
                            <li>elem1_1</li>  
                          </ol>
                      </li>
                    </ul>
                </div>
            </li>
        </ol>
    </li>
    <li>elem2</li>
</ul>
<ul>
    <li>Point:
        <div>
            <ul>
                <li>elem1</li>
            </ul>
        </div>
    </li>
</ul>
<ul>
    <li>simple list1</li>
</ul>

<hr />

<div id="result"></div>

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mixed-type, variable length argument list (varargin, *args, ...) for C++

By : Steven Wojcio

Date : March 29 2020, 07:55 AM

I wish this help you If you only want to pass arguments of a few (simple) types, std::vector<> passed as argument is pretty straightforward and easy.
Usually you will create struct such as:

code :

struct Option {
    union {
        int Int;
        float Float;
    } Number;
    string String;
};

Convert Mixed-Length named List to data.frame

By : Gong Szeto

Date : March 29 2020, 07:55 AM

will help you Here's my initial thought. It doesn't speed up your approach, but it does simplify the code considerably:

code :

# makeDF <- function(List, Names) {
#     m <- t(sapply(List, function(X) unlist(X)[Names], 
#     as.data.frame(m)
# }    

## vapply() is a bit faster than sapply()
makeDF <- function(List, Names) {
    m <- t(vapply(List, 
                  FUN = function(X) unlist(X)[Names], 
                  FUN.VALUE = numeric(length(Names))))
    as.data.frame(m)
}

## Test timing with a 50k-item list
ll <- createList(50000)
nms <- c("a", "b", "c")

system.time(makeDF(ll, nms))
# user  system elapsed 
# 0.47    0.00    0.47

how to find out the length of a list in jquery after filtering the list using a function

By : Clay

Date : March 29 2020, 07:55 AM

it should still fix some issue If you hide the filtered items, you can count the not-hidden elements this way:

code :

$("#mylistid li:visible").length

Conver Mixed-Length 1 level deep list to data frame

By : parsa

Date : March 29 2020, 07:55 AM

I wish this helpful for you I have a list as follows: , How about this?

code :

x <- list(A = "one", 
          B = "Two", 
          c = "Three", 
          D = c("Four", "Five"), 
          E = c("Six", "Seven"))

df <- data.frame(Var1 = rep(names(x), sapply(x, length)),
                 Var2 = unlist(x, use.names = F))

Taking Mixed-Length List to data.frame with correct headers

By : BarelyAgileRob

Date : March 29 2020, 07:55 AM

will be helpful for those in need I have a list that looks something like this, where the variables are of various lengths, and in a random order , You could use a lookup vector and match against it.