D3 scale.invert() isn't returning date for x

D3 scale.invert() isn't returning date for x

By : nabilanil
Date : November 29 2020, 09:01 AM
Hope this helps Using the method Nithin CV Poyyil recommended to determine the output of the actual data, to solve this problem, i had to do 2 things.
1 - in my backend app, convert the date from a string like '2015-11-02' to an epoch time in milliseconds, before sending it to the view to be used by d3.js. this made it easier to work with, probably should do this all the time from now on until forever.
code :
function mousemove() {
    var xScale = d3.time.scale()
    .domain([d3.min(linedata, function(d) { return d.date; }), d3.max(linedata, function(d) { return d.date; })])
    .range([0, w + 170] );

    var yScale = d3.scale.linear()
    .domain([amount_min, amount_max])
    .range([h, 0])

    var bisectDate = d3.bisector(function(d) { return d.date; }).left;
    var dateFormat = d3.time.format('%d. %b')

    var xPosition = xScale.invert(d3.mouse(this)[0]),//xScale.invert(d3.mouse(this)[0]), //<-- give me the date at the x mouse position
        closestElement = bisectDate(linedata, xPosition, 1), //<-- use the bisector to search the array for the closest point to the left and find that point given our mouse position
        d0 = linedata[closestElement - 1],
        d1 = linedata[closestElement],
        d = xPosition - d0.date > d1.date - xPosition ? d1 : d0;

    focus.attr("transform", "translate(" + xScale(d.date) + "," + yScale(d.amount) + ")");
    focus.select("text").text("Amount: " + d.amount + " Date: " + d.date);

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PHP how to invert a scale of numbers

PHP how to invert a scale of numbers

By : MTA
Date : March 29 2020, 07:55 AM
I wish this help you The formula is $new = -$old + 6. Just use it with array_map
Invert scale function

Invert scale function

By : William Sant Ana
Date : March 29 2020, 07:55 AM
this will help This is interesting to me. Look at the following D3 code: , Yes, there is, and it's aptly named invert.
code :
console.log(scale.invert(10));   //Returns 100
console.log(scale.invert(180));  //Returns 300
console.log(scale.invert(350));  //Returns 500
Invert a color scale in d3.js

Invert a color scale in d3.js

By : user3387646
Date : March 29 2020, 07:55 AM
this one helps. According to the documentation:
D3: am I using scale.invert() wrong?

D3: am I using scale.invert() wrong?

By : LewisWeekly
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , Your code doesn't work correctly because the scale gives you a position, not a difference between positions. That is, when inverting you're getting the datum for a particular pixel location, not a difference between two pixel locations. It's safer to compute the new position (in pixels, by adding the offset) and then invert that:
code :
for(var i = 1; i<dataset.length;i++){
  var diff = xScale(dataset[i]) - xScale(dataset[i-1]);
  if(diff < 2*dotRad) {
    var add = 2 * dotRad - diff;
    dataset[i] = xScale.invert(xScale(dataset[i]) + add);
Invert the scale of an array

Invert the scale of an array

By : ImConfusedlol
Date : March 29 2020, 07:55 AM
Hope this helps Say I have the following array: , Here is a numpy way:
code :
ax = np.argsort(x)
aax = np.zeros(len(ax),dtype='int')
aax[ax] = np.arange(len(ax),dtype='int')

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