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Permute string until it matches some input?


Permute string until it matches some input?

By : Soumyabrata13
Date : December 01 2020, 05:00 PM
around this issue Here is the fiddle
code :
 var alphabet = ['a','b','c'];//,'d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z'];

 var output = "";
 var match = "cccc";  //<----------- match here

//This is your main function 
function permutate() {

    var d = 0;   // d for depth

    while (true) {

       //Your main alphabet iteration             
       for (var i=0; i<alphabet.length; i++){

          //First level 
          if (d === 0) {
             console.log(alphabet[i])
             output = alphabet[i];
          }    
          else
             iterator(alphabet[i], d);   //Call iterator for d > 0

          if (output === match)
             return;
          }


          d++;  //Increase the depth
       }
 }


 //This function runs n depths of iterations
 function iterator(s, depth){

    if (depth === 0)
       return;

    for (var i=0; i<alphabet.length; i++){

       if (depth > 1)
          iterator(s + alphabet[i], depth - 1)
       else {
          console.log(s + alphabet[i]);
          output = s + alphabet[i];
       } 

       if (output === match)
          return;
    }

 };                
[a] 
    -[a]
        -[a] 
             -[a]...
             -[b]...

         [b] ...
    -[b] -
         -[a]...
         -[b]...

[b] - ...
[c] - ...


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Matlab: How to randomly permute and inverse permute a vector

Matlab: How to randomly permute and inverse permute a vector


By : Shishir Dahake
Date : March 29 2020, 07:55 AM
will be helpful for those in need I need to implement the following algorithm in Matlab. , You can actually put the indexing on the left hand side:
code :
A(index) = A;
How to input strings into array until input string matches criteria?

How to input strings into array until input string matches criteria?


By : Candy John
Date : March 29 2020, 07:55 AM
To fix this issue I can't even begin to correct your code. To achieve what you want to do try this:
code :
    Scanner in = new Scanner(System.in);
    ArrayList<String> list = new ArrayList<String>();
    String line;
    while (!(line = in.nextLine()).equals("stop")) {
        list.add(line);
    }
    in.close();
    System.out.println(list);
Nd4j permute does not permute - what have I done wrong?

Nd4j permute does not permute - what have I done wrong?


By : S. Walsh
Date : March 29 2020, 07:55 AM
it fixes the issue According to the documentation you linked to, permute method is used to permute the dimensions of a multi-dimensional array. Nd4j.linspace creates a vector (a 1-dimensional array). Since there is only one dimension, there is no other dimension to permute it with. The example on Mathworks on the other hand, creates a 3-dimentional array and permutes the 1st and 3rd dimension.
It sounds like your intention was to permute the individual elements of an array (not entire dimensions). I haven't seen a method for that in Nd4j.
How to check if the input string from Scanner Util matches an initial string

How to check if the input string from Scanner Util matches an initial string


By : user286113
Date : March 29 2020, 07:55 AM
wish of those help you could use the .equals() method to comapare two values to see if they match.
code :
pinnum.equals(s)
Attempting to extract one of two possible words from a text string if matches a criteria, or input the string in it's en

Attempting to extract one of two possible words from a text string if matches a criteria, or input the string in it's en


By : mikemimik
Date : March 29 2020, 07:55 AM
I wish this help you You can use:
code :
=IF(ISNUMBER(SEARCH("*local*",A1)),"Local",IF(ISNUMBER(SEARCH("*national*",A1)),"national",A1))
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