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CUDA QUESTIONS

the Difference between running time and time of obtaining results in CUDA
the Difference between running time and time of obtaining results in CUDA
it should still fix some issue The confusion here seems to have arisen out of using a host-based timing method to time what is (mostly) device activity.Kernel launches are asynchronous. The host code launches the kernel, and then proceeds without wai
TAG : cuda
Date : November 25 2020, 09:00 AM , By : Shuopeng LI
Eliminate cudaMemcpy between kernel calls
Eliminate cudaMemcpy between kernel calls
Does that help I've got a CUDA kernel that is called many times (1 million is not the limit). Whether we launch kernel again or not depends on flag (result_found), that our kernel returns. , 1) Is there any way to avoid calling cudaMemcpy here?
TAG : cuda
Date : November 21 2020, 09:01 AM , By : JamMcT
Finding device ID from kernel thread
Finding device ID from kernel thread
it fixes the issue If your device supports cuda dynamic parallelism, you can use the cudaGetDevice() call in device code as documented here:
TAG : cuda
Date : November 21 2020, 07:38 AM , By : desyfer
CUDA : cuSolver raises an exception
CUDA : cuSolver raises an exception
this will help I am trying to use cusolver library to solve a number of linear equations but instead an exception is raised which is very strange. the code is using only one function from the library and the rest is memory allocation and memory copy.
TAG : cuda
Date : November 14 2020, 07:01 AM , By : user4573628
Installing CUDA as a non-root user with no GPU
Installing CUDA as a non-root user with no GPU
hop of those help? Assuming you want to develop codes that use the CUDA runtime API, you can install the cuda toolkit on a system that does not have a GPU. Using the runfile installer method, simply answer no when prompted to install the driver.
TAG : cuda
Date : November 07 2020, 09:00 AM , By : johann
The computation of global memory load transactions in CUDA kernel
The computation of global memory load transactions in CUDA kernel
I wish this helpful for you There is only a small point that you missed. Global memory access is coalesced only for threads within a warp (see the programming guide). In your case there are 4 warps. Each will need one memory transaction for the eleme
TAG : cuda
Date : October 28 2020, 08:10 AM , By : Jordan Service
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